SQL如何将行转换为列，将行转换为行？ db2

Question

我有一个在DB2中正常工作的SQL查询，我的结果是

SERVICE   IN   OUT   INPROGRESS

ADSL      1     5      10
VOIP      15    12     11
IPTV      20    14     17

现在，我想将其转换为如下形式：

CLASS       ADSL   VOIP   IPTV

IN           1     5      10
OUT          15    12     11
INPROGRESS   20    14     17

虽然看起来我的SQL很长很简单，但是我从未改变过它。 如果有人知道我会很感激的。

我的SQL是

select  distinct 'ADSL' as SERVICE,

(select count(*) as In from ticket 
where 
(class='C1'  and
(servicesinfault='25'))),

(select count(*) as Out from ticket
where 
(class='C2' and
(servicesinfault='25'))),


(select count(*) as In_progress from ticket
where 
(class='C3' and
(servicesinfault='25')))

from ticket where servicesinfault = '25'

union all

select  distinct 'VoIP',

(select count(*) from ticket 
where
(class='C1'  and
(servicesinfault='26'))),

(select count(*) from ticket
where
(class='C2'  and
(servicesinfault='26'))),


(select count(*) from ticket
where 
(class='C3'  and
(servicesinfault='26')))

from ticket where servicesinfault = '26'

union all

select  distinct 'IPTV',

(select count(*) from ticket 

where 
(class='C1'  and
(ticket.servicesinfault='27'))),

(select count(*) from ticket
where 
(class='C2'  and
(servicesinfault='27'))),

(select count(*) from ticket
where 
(class='C3'  and
(servicesinfault='27')))

from ticket where servicesinfault = '27'

Answer 1

谨此声明，您的结果应为：

CLASS       ADSL   VOIP   IPTV

IN           1     15     20
OUT          5     12     14
INPROGRESS   10    11     17

透视版本应为：

select distinct 'In' as CLASS,

                (select count(*) as 'ADSL'
                   from ticket
                  where (class = 'C1' and (servicesinfault = '25'))),

                (select count(*) as 'VoIP'
                   from ticket
                  where (class = 'C1' and (servicesinfault = '26'))),

                (select count(*) as 'IPTV'
                   from ticket
                  where (class = 'C1' and (servicesinfault = '27')))

  from ticket
 where class = 'C1'

union all

select distinct 'Out',

                (select count(*)
                   from ticket
                  where (class = 'C2' and (servicesinfault = '25'))),

                (select count(*)
                   from ticket
                  where (class = 'C2' and (servicesinfault = '26'))),

                (select count(*)
                   from ticket
                  where (class = 'C2' and (servicesinfault = '27')))

  from ticket
 where class = 'C2'

union all

select distinct 'InProgress',

                (select count(*)
                   from ticket

                  where (class = 'C3' and (ticket.servicesinfault = '25'))),

                (select count(*)
                   from ticket
                  where (class = 'C3' and (servicesinfault = '26'))),

                (select count(*)
                   from ticket
                  where (class = 'C3' and (servicesinfault = '27')))

  from ticket
 where class = 'C3'

Answer 2

您要查找的单词是“ PIVOT”。

如果您的DBMS不提供，则可以使用“穷人的支点”。

查看usr关于此问题的答案：

可怜的人的SQL枢轴。 在每一行中将问题列为每位用户的列和答案