在ListView中获取绝对视图位置

Question

我试图让一个弹出窗口出现在ListView内部单击的项目上方/下方。 但是，问题是从OnItemClick方法进入的View只给出了它相对于ListView本身的X和Y值。 我还检查了ListView，这也给了我x = 0 y = 0，尽管它上面还有其他视图。

我遍历了hierarchyviewer中的所有值，但没有看到我正在寻找的值。 （而不是我在重新开始工作时遇到重大问题）。

有什么建议？

@Override
public void onListItemClick(ListView listView, View view, int position, long id) {
    LayoutInflater inflater = getLayoutInflater(null);
    PopupWindow quickRail = new PopupWindow(
            inflater.inflate(R.layout.quanitity_controls, null), view.getMeasuredWidth(),
            view.getMeasuredHeight());

    int[] location = {
            0, 0
    };

    // This doesn't place this window right on top of the view
    quickRail.showAtLocation(view, Gravity.CENTER, 0, location[1]);
}

列表中的两个项目都使Popup出现在同一个位置。

Answer 1

这应该工作

//Activity windows height
int totalHeight = getWindowManager().getDefaultDisplay().getHeight();
int[] location = new int[2];
v.getLocationOnScreen(location);

位置数组应具有视图的x和y值。 'v'是onItemClickListener上传递的视图对象。

我添加了一些我用于项目的部分。 它可能会有所帮助。 我在listview的顶部有一个操作栏，这段代码似乎运行正常。

要求是在列表项的顶部或下方放置一个小菜单。 因此，当选择一个项目时，我检查所选列表项是否在屏幕的上半部分，如果是这样，则将菜单放在列表项目下面，否则将其放在列表项目的顶部。 这是代码

ListItem单击代码

listView.setOnItemClickListener(new OnItemClickListener() {
    public void onItemClick(AdapterView<?> parent, View view, int position
           , long id) {
        showQuickActionMenu(position,view);
    }   
});

private void showQuickActionMenu(int pos, View v){
    LayoutInflater inflater = 
            (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    //This is just a view with buttons that act as a menu.  
    View popupView = inflater.inflate(R.layout.ticket_list_menu, null);
    popupView.findViewById(R.id.menu_view).setTag(pos);
    popupView.findViewById(R.id.menu_change_status).setTag(pos);
    popupView.findViewById(R.id.menu_add_note).setTag(pos);
    popupView.findViewById(R.id.menu_add_attachment).setTag(pos);

    window = PopupHelper.newBasicPopupWindow(TicketList.this);
    window.setContentView(popupView);
    int totalHeight = getWindowManager().getDefaultDisplay().getHeight();
    int[] location = new int[2];
    v.getLocationOnScreen(location);

    if (location[1] < (totalHeight / 2.0)) {
        PopupHelper.showLikeQuickAction(window, popupView, v
                , getWindowManager(),0,0,PopupHelper.UPPER_HALF);
    } else {
        PopupHelper.showLikeQuickAction(window, popupView, v
                , getWindowManager(),0, 0,PopupHelper.LOWER_HALF);
    }   
}

这是我使用的PopupHelper类

public class PopupHelper {
    public static final int UPPER_HALF = 0;
    public static final int LOWER_HALF = 1;

    public static PopupWindow newBasicPopupWindow(Context context) {
        final PopupWindow window = new PopupWindow(context);

        // when a touch even happens outside of the window
        // make the window go away
        window.setTouchInterceptor(new OnTouchListener() {
            public boolean onTouch(View v, MotionEvent event) {
                if(event.getAction() == MotionEvent.ACTION_OUTSIDE) {
                    window.dismiss();
                    return true;
                }
                return false;
            }
        });

        window.setWidth(WindowManager.LayoutParams.WRAP_CONTENT);
        window.setHeight(WindowManager.LayoutParams.WRAP_CONTENT);
        window.setTouchable(true);
        window.setFocusable(true);
        window.setOutsideTouchable(true);

        window.setBackgroundDrawable(
                new ColorDrawable(android.R.color.darker_gray));        
        return window;
    }

    /**
     * Displays like a QuickAction from the anchor view.
     * 
     * @param xOffset
     *            offset in the X direction
     * @param yOffset
     *            offset in the Y direction
     */
     public static void showLikeQuickAction(PopupWindow window, View root, 
             View anchor, WindowManager windowManager, int xOffset
             ,int yOffset,int section) {

         //window.setAnimationStyle(R.style.Animations_GrowFromBottomRight);

         int[] location = new int[2];
         anchor.getLocationOnScreen(location);

         Rect anchorRect = new Rect(location[0], location[1], location[0] + 
                 anchor.getWidth(), location[1] + anchor.getHeight());

         root.measure(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);

         int rootWidth = root.getMeasuredWidth();
         int rootHeight = root.getMeasuredHeight();

         int screenWidth = windowManager.getDefaultDisplay().getWidth();
         int screenHeight = windowManager.getDefaultDisplay().getHeight();

         int xPos = ((screenWidth - rootWidth) / 2) + xOffset;
         int yPos = anchorRect.top - rootHeight + yOffset;

         xPos = (screenWidth - rootWidth);
         if(section == UPPER_HALF){
             yPos = anchorRect.top + anchor.getMeasuredHeight();    
         } else {
             yPos = anchorRect.top - rootHeight;
         }
         window.showAtLocation(anchor, Gravity.NO_GRAVITY, xPos, yPos);
    }

}

Answer 2

对于那些坚持这个问题的人，请尝试使用此代码段

popWindow.showAsDropDown(v);//v is your listview or recyclerview item Element that clicked.

希望这个帮助。

Answer 3

试试这个，看它是否有效..

private  void setListViewHeightBasedOnChildren(ListView listView) {
    ListAdapter listAdapter = listView.getAdapter();
    if (listAdapter == null) {
        // pre-condition
        return;
    }
    int totalHeight = 0;
    int desiredWidth = MeasureSpec.makeMeasureSpec(listView.getWidth(), MeasureSpec.AT_MOST);
    for (int i = 0; i < listAdapter.getCount(); i++) {
        View listItem = listAdapter.getView(i, null, listView);
        listItem.measure(desiredWidth, MeasureSpec.UNSPECIFIED);
        totalHeight += listItem.getMeasuredHeight();
    }

}

//这里listItem.getMeasuredHeight（）会得到你每个列表项的高度...你可以通过高度得到你的位置* clickedPosition