准时读取来自GCDAsyncSocket的响应（iOS）

Question

这个问题很简单，我只是很难弄清楚如何处理它。

我用以下方式读取数据：

[asyncSocket readDataWithTimeout:-1 tag:2];

NSString *failure = [serverJSONResponseParsed objectForKey:@"failure"];
NSLog(@"Contents of string failure: %@", failure);

if ([failure isEqualToString:@"none"]) {
    NSLog(@"Success Sending String");
    return TRUE;
}
else {
    NSLog(@"Failure: %@",failure);
    return FALSE;
}

现在，正如预期的那样，我的委托方法被调用并正确读取JSON数据：

-(void)socket:(GCDAsyncSocket *)sock didReadData:(NSData *)data withTag:(long)tag {
    NSError *error;
    NSLog(@"didReadData: %@", [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]);
    serverJSONResponseParsed = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
    NSLog(@"didReadData test after dict: %@", [serverJSONResponseParsed objectForKey:@"failure"]);
}

问题是，由于GCDAsyncSocket是异步的，所以此代码块

NSString *failure = [serverJSONResponseParsed objectForKey:@"failure"];
NSLog(@"Contents of string failure: %@", failure);

if ([failure isEqualToString:@"none"]) {
    NSLog(@"Success Sending String");
    return TRUE;
}
else {
    NSLog(@"Failure: %@",failure);
    return FALSE;
}

后

[asyncSocket readDataWithTimeout:-1 tag:2];

在有机会读取数据之前调用它。我将如何确保读取数据，然后对其进行分析。

Answer 1

该代码块必须位于didReadData回调方法中，如下所示：

    -(void)socket:(GCDAsyncSocket *)sock didReadData:(NSData *)data withTag:(long)tag {
        NSError *error;
        NSLog(@"didReadData: %@", [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]);
        serverJSONResponseParsed = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
        NSLog(@"didReadData test after dict: %@", [serverJSONResponseParsed objectForKey:@"failure"]);

    NSString *failure = [serverJSONResponseParsed objectForKey:@"failure"];
    NSLog(@"Contents of string failure: %@", failure);

    if ([failure isEqualToString:@"none"]) {
        NSLog(@"Success Sending String");
        return TRUE;
    }
    else {
        NSLog(@"Failure: %@",failure);
        return FALSE;
    }
}