运行服务时唤醒锁定

Question

我只是想知道这是实现唤醒锁定以使设备进入睡眠模式后重新启动的正确方法。 重新启动设备后，它将从该点启动意图。 真的，我只是想让屏幕显示足够长的时间，以使意图发生。 如果没有指针，我是否正确执行此操作！

public class GMeter extends Service implements SensorEventListener {

private float mLastX, mLastY, mLastZ;
private boolean mInitialized;
private SensorManager mSensorManager;
private Sensor mAccelerometer;
private final float NOISE = (float) 2.0;
private PowerManager.WakeLock wl;

/** Called when the activity is first created. */
public void onCreate() {
    mInitialized = false;
    mSensorManager = (SensorManager) getSystemService(Context.SENSOR_SERVICE);
    mAccelerometer = mSensorManager
            .getDefaultSensor(Sensor.TYPE_ACCELEROMETER);
    mSensorManager.registerListener(this, mAccelerometer,
            SensorManager.SENSOR_DELAY_NORMAL);
    Toast.makeText(this, "Starting Service", Toast.LENGTH_LONG).show();
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
    return START_STICKY;
}

@Override
public void onAccuracyChanged(Sensor arg0, int arg1) {
    // TODO Auto-generated method stub

}

@Override
public void onSensorChanged(SensorEvent event) {
    float x = event.values[0];
    float y = event.values[1];
    float z = event.values[2];
    double a = Math.sqrt(Math.pow(x, 2) + Math.pow(y, 2));
    double currentG = (a / SensorManager.STANDARD_GRAVITY);
    if (!mInitialized && currentG > 0.5) {
        AlertDialog alert = new AlertDialog.Builder(GMeter.this).create();
        alert.setTitle("-=Warning=-");
        alert.setMessage("Incoming Game!");
        alert.show();
        PowerManager pm = (PowerManager) getSystemService(Context.POWER_SERVICE);
        wl = pm.newWakeLock(PowerManager.ACQUIRE_CAUSES_WAKEUP + PowerManager.FULL_WAKE_LOCK, "myTag");
        wl.acquire();
        wl.release();
        mLastX = x;
        mLastY = y;
        mLastZ = z;
        mInitialized = true;
        // Start Second Activity
        Intent intent = new Intent(GMeter.this, nextClass.class);
        intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        startActivity(intent);
    } else {
        float deltaX = Math.abs(mLastX - x);
        float deltaY = Math.abs(mLastY - y);
        float deltaZ = Math.abs(mLastZ - z);
        if (deltaX < NOISE)
            deltaX = (float) 0.0;
        if (deltaY < NOISE)
            deltaY = (float) 0.0;
        if (deltaZ < NOISE)
            deltaZ = (float) 0.0;
        mLastX = x;
        mLastY = y;
        mLastZ = z;
    }
}

@Override
public IBinder onBind(Intent intent) {
    // TODO Auto-generated method stub
    return null;
}

}

Answer 1

不，唤醒锁用于防止设备进入睡眠状态。 我猜您应该使用AlarmManager功能来唤醒设备并发送一个意图（带有参数RTC_WAKEUP ）。

编辑：如果要在服务的onCreate()方法中实现功能，则应获取PARTIAL_WAKE_LOCK，并应在onDestroy()释放它。 因此，您的服务将收到通知。 或者，您可以每n秒唤醒一次设备并检查传感器。