检查字符串中是否包含单词数组

Question

我们在PHP中有一个函数in_array ，它检查给定值是否存在于数组中。 我想我想做相反的事情。 我有一组字符串：

$words = array("hello", "world");

而且，我想通过给定参数all或any检查给定的字符串是否包含这些单词。

$string = "Hello, World!";
$second = "Hello and Welcome!";
in_string($words, $string, "all");
in_string($words, $string, "any");

我现在拥有的是使用stripos() 。 我不想使用regex 。

当前代码：

<?php
    /**
    * Checks if the given words is found in a string or not.
    * 
    * @param Array $words The array of words to be given.
    * @param String $string The string to be checked on.
    * @param String $option all - should have all the words in the array. any - should have any of the words in the array
    * @return boolean True, if found, False if not found, depending on the $option
    */
    function in_string ($words, $string, $option)
    {
        if ($option == "all")
            foreach ($words as $value)
                $isFound = $isFound && (stripos($string, $value) || false);
        else
            foreach ($words as $value)
                $isFound = $isFound || (stripos($string, $value) || false);
        return $isFound;
    }
?>

我的问题是，这可以改善吗？ 有什么想法吗？

---

更新＃1：当前代码已更新：

/**
* Checks if the given words is found in a string or not.
* 
* @param Array $words The array of words to be given.
* @param String $string The string to be checked on.
* @param String $option all - should have all the words in the array. any - should have any of the words in the array
* @return boolean True, if found, False if not found, depending on the $option
*/
function in_string ($words, $string, $option)
{
    if ($option == "all")
    {
        $isFound = true;
        foreach ($words as $value)
            $isFound = $isFound && (stripos($string, $value) !== false);
        return $isFound;
    }
    else
    {
        $isFound = true;
        foreach ($words as $value)
            if (stripos($string, $value) !== false) return true;
        return $isFound;
    }
}

现在，该功能可以按预期运行。 但是我需要在foreach()部分以及所有方面都有更好的性能。 有什么改进的可能吗？

---

更新＃2：添加了改进

<?php
    /**
    * Checks if the given words is found in a string or not.
    * 
    * @param Array $words The array of words to be given.
    * @param String $string The string to be checked on.
    * @param String $option all - should have all the words in the array. any - should have any of the words in the array
    * @return boolean True, if found, False if not found, depending on the $option
    */
    function in_string ($words, $string, $option)
    {
        if ($option == "all")
        {
            foreach ($words as $value)
                if (stripos($string, $value) === false)
                    return false;
            return true;
        }
        else
        {
            foreach ($words as $value)
                if (stripos($string, $value) !== false)
                    return true;
            return false;
        }
    }
?>

Answer 1

<?php
/**
* Checks if the given words is found in a string or not.
* 
* @param Array $words The array of words to be given.
* @param String $string The string to be checked on.
* @param String $option all - should have all the words in the array. any - should have any of the words in the array
* @return boolean True, if found, False if not found, depending on the $option
*/
function in_string ($words, $string, $option)
{
    if ($option == "all") {
        $isFound = true;
        foreach ($words as $value) {
            $isFound = $isFound && (stripos($string, $value) !== false); // returns boolean false if nothing is found, not 0
            if (!$isFound) break; // if a word wasn't found, there is no need to continue
        }
    } else {
        $isFound = false;
        foreach ($words as $value) {
            $isFound = $isFound || (stripos($string, $value) !== false);
            if ($isFound) break; // if a word was found, there is no need to continue
        }
    }
    return $isFound;
}
?>

和我下面的人一样的代码，只是休息了； 添加。 我没有足够的代表来评论

Answer 2

分开逻辑，您将在每个函数中获得更简单的代码，更好的性能，并且每个函数都将解决具体任务。

<?php
function in_string_all ($string, $words) {
    $isFound = true;
    foreach ($words as $value) {
        $isFound = $isFound && stripos($string, $value) !== false;
        if (!$isFound) 
            break;
    }
    return $isFound;
}

function in_string_any ($string, $words) {
    foreach ($words as $value) 
        if (stripos($string, $value) !== false)
            return true;
    return false;
}
?>

Answer 3

使用strpos无效，因为对于部分字符串匹配，它将返回true。 在“ insersection”中搜索“ in”的示例将导致误报。 这是从目标字符串中提取单词并在数组之间进行交集的一种替代方法。

/**
 * Checks if a array of given words is found in a string.
 * 
 * @param array $words The array of words to be given.
 * @param string $string The string to be checked on.
 * @param boolean $exactMatch true - should have all the words in the array. false - should have any of the words in the array
 * @param boolean $insensitive true to compare insensitive. false to compare sensitive
 * @return boolean True, if found, False if not found, depending on the $option
 */
private function arrayInString (array $words, $string, $exactMatch = true, $insensitive = true)
{
    $stringArr = explode(" ", preg_replace('/[^a-z0-9]+/i', ' ', $string));
    if ($insensitive) {
        $words = array_map('strtolower', $words);
        $stringArr = array_map('strtolower', $stringArr);
    }
    $intersectionCount = count(array_intersect($words, $stringArr));
    if ($exactMatch && $intersectionCount == count($words)) {
        return true;
    }
    if (!$exactMatch && $intersectionCount > 0) {
        return true;
    }

    return false;
}

Answer 4

使用strpos()而不是substr()或strstr()因为您只在乎出现的单词，不需要解析任何内容。 根据文档，它更快。

从手册 ：

如果只想确定干草堆中是否有特定的针头，请改用速度更快且占用内存较少的函数strpos（）。

Answer 5

您需要初始化$isFound ，对不区分大小写的搜索使用stripos() ，并检查stripos()返回false而不是0。（0表示$string以$value开头）

function in_string ($words, $string, $option)
{
if ($option == "all") {
    $isFound = true;
    foreach ($words as $value) {
        $isFound = $isFound && (stripos($string, $value) !== false);
    }
} else {
    $isFound = false;
    foreach ($words as $value) {
        $isFound = $isFound || (stripos($string, $value) !== false);
    }
}
return $isFound;
}