JSP Servlet请求的资源（）不可用[重复]

Question

这个问题已经在这里有了答案：

• Servlet返回“ HTTP状态404请求的资源（/ Servlet）不可用” 9个答案

当我尝试提交要由servlet处理的表单时，浏览器指示请求的资源不可用，并出现HTTP 404错误。 该URL看起来像：

http://localhost:8080/Website/DateSearchServlet

我的XML文件：

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
    <servlet-name>DateSearchServlet</servlet-name>
    <servlet-class>DB.DateSearchServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>DateSearchServlet</servlet-name>
    <url-pattern>/Search/*</url-pattern>
</servlet-mapping>
<session-config>
    <session-timeout>
        30
    </session-timeout>
</session-config>

要调用servlet，我正在使用以下简单形式：

<form name="dateSearch" action="DateSearchServlet" method="post">
    <label for="from">Date From</label>
    <input type="text" id="from" name="from" />
    <label for="to">Date To</label>
    <input type="text" id="to" name="to" />
    <input type="submit" id="submit" value="Submit">
</form>

最后是servlet：

@WebServlet(name = "DateSearchServlet", urlPatterns = {"/Search"})
public class DateSearchServlet extends HttpServlet {

DatabaseConnector dataManager;
boolean dbOK = false;
HomeList homes = new HomeList();

@Override
public void init() {
    dataManager = new DatabaseConnector();
}

@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    String dateFrom = request.getParameter("from");
    String dateTo = request.getParameter("to");

    if (dateFrom == null || dateTo == null) {
        dbOK = false;
    } else {
        dbOK = true;
    }//end if

    request.setAttribute("homeList", null);

    if (dbOK) {
        homes = dataManager.getPropertiesSearch(dateFrom, dateTo);
        request.setAttribute("homeList", homes);
        request.getRequestDispatcher("bookings.jsp").forward(request, response);
    } else {
        System.out.println("DBNOTOK");
        //error...
    }
}
}

谢谢

Answer 1

对于正在调用的servlet，没有正确配置web.xml中的URL模式。

因此，将表单中的操作更改为URL Search / DateSearchServlet

Answer 2

试试这个...

<form name="dateSearch" action="DateSearchServlet.action" method="post">
<label for="from">Date From</label>
<input type="text" id="from" name="from" />
<label for="to">Date To</label>
<input type="text" id="to" name="to" />
<input type="submit" id="submit" value="Submit">