MYSQL / PHP选择相同的值

Question

我有一张桌子，上面有可以订购的产品。

╔═════════╦═════════╗
║ ORDERID ║ INSTORE ║
╠═════════╬═════════╣
║       1 ║       0 ║
║       1 ║       1 ║
║       1 ║       1 ║
║       1 ║       1 ║
║       1 ║       0 ║
║       2 ║       1 ║
║       2 ║       1 ║
║       2 ║       1 ║
╚═════════╩═════════╝

现在，我需要获取所有instore都具有值1的订单，例如orderid2。 这怎么可能？

所需结果

╔═════════╗
║ ORDERID ║
╠═════════╣
║       2 ║
╚═════════╝

Answer 1

SELECT  orderID
FROM    tableName
GROUP   BY orderID
HAVING  COUNT(*) = SUM(instore = 1)

• SQLFiddle演示

Answer 2

SELECT * FROM products p WHERE not exists (select 1 from products where orderid = p.orderid and instore != 1 limit 1)

Answer 3

不知道我是否完全理解你的问题，但是

select * from products where instore=1 and orderid=2;

Answer 4

SELECT DISTINCT (

订单ID）FROM products WHERE店内= 1 AND订单ID NOT IN（

从产品中选择订单ID Instore = 0）