[英]Add a node in ascending order
def add(self, value):
#write your code here
if self.head == None:
new_node = Node(value)
self.head = new_node
self.tail = self.head
elif self.head.value > new_node.value:
new_node = Node(value)
new_node.value = value
new_node.next = self.head
self.head = new_node
else:
new_node = Node(value)
self.tail.setNext(new_node)
self.tail = new_node
self.count += 1
上面是我的函數添加的代碼。 我試圖將Node
對象按升序添加到鏈接列表中,以便在打印時它顯示為:
>>> x.add(8)
>>> x.add(7)
>>> x.add(3)
>>> x.add(-6)
>>> x.add(58)
>>> x.add(33)
>>> x.add(1)
>>> x.add(-88)
>>> print(x)
Head:Node(-88) Tail:Node(58)
List:-88 -6 1 3 7 8 33 58
但是,當我在上面的代碼中執行此操作時,它會將其打印為:
>>> print(x)
Head:Node(-88)
Tail:Node(1)
List:-88 -6 3 7 8 58 33 1
我80%確信問題出在elif語句內,但我不確定如何解決此問題以使其升序。
問題出在最后。 讓我們看看發生了什么:數字,動作,結果:
58->最后---6、3、7、8、58
當33到來並再次進入最后一個錯誤時,這里出現錯誤,因為它比-6的head大,結果變為-6、3、7、8、58、33。
要解決此問題,您需要遍歷列表以查看需要放置33的位置,僅通過將項目放在開頭或末尾就無法獲得排序列表。
def add(self, value):
#write your code here
#if list is empty
if self.head == None:
new_node = Node(value)
self.head = new_node
self.tail = self.head
#elif value < head set new head
elif self.head.value > value:
new_node = Node(value)
new_node.value = value
new_node.next = self.head
self.head = new_node
#elif value > tail set new tail
elif value > self.tail.value:
new_node = Node(value)
self.tail.setNext(new_node)
self.tail = new_node
# and finally you need to loop to find the sweet spot
else:
# we will start the search from the head
current_node = self.head
# while the value we wish to insert is bigger than the next one
while value > current_node.next.value:
# set the current one to the next one
current_node = current_node.next
# finally we reached a node which is smaller than the value we wish to insert
# but its next node is bigger
new_node = Node(value)
# set the new nodes next to the bigger node
new_node.next = current_node.next
# and the curren't node's next to the new one
current_node.next = new_node
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