在 JavaScript 中處理對象數組的數據 [重復]

Question

這個問題在這里已經有了答案：

Javascript：將具有打開時間的對象數組轉換為單個字符串2 個答案

3天前關閉。

我有下面的數組。

Const array = [
  {
    "day": "Monday",
    "beginHour": "08:30:00",
    "endHour": "17:00:00"
  },
  {
    "day": "Tuesday",
    "beginHour": "08:30:00",
    "endHour": "17:00:00"
  },
  {
    "day": "Wednesday",
    "beginHour": "08:30:00",
    "endHour": "17:00:00"
  },
  {
    "day": "Thursday",
    "beginHour": "08:30:00",
    "endHour": "17:00:00"
  },
  {
    "day": "Friday",
    "beginHour": "08:30:00",
    "endHour": "17:00:00"
  }
]

我正在 NodeJs 中編寫一個函數來處理這種數組，其中辦公時間和日期可能會根據辦公室而變化。 我試圖返回低於值。

response = "Mon-Fri 8.30-5pm Closed Sat & Sun"

請建議/建議。 萬分感激。

Answer 1

有一個解決方案....試試看：

 const array = [ { "day": "Monday", "beginHour": "08:30:00", "endHour": "17:00:00" }, { "day": "Tuesday", "beginHour": "08:30:00", "endHour": "17:00:00" }, { "day": "Wednesday", "beginHour": "08:30:00", "endHour": "17:00:00" }, { "day": "Thursday", "beginHour": "08:30:00", "endHour": "17:00:00" }, { "day": "Friday", "beginHour": "08:30:00", "endHour": "17:00:00" } ]; //create a function const days = arr => { //get days and time const [mon,fri] = [arr[0],arr[arr.length-1]]; //destructure const [dayM,openM,closeM] = Object.values(mon); const [dayF,openF,closeF] = Object.values(fri); return `${dayM}-${dayF} ${openM}-${closeF} Closed Sat & Sun.`; }; console.log(days(array));