Mysql 查詢返回重復結果哪個分頁

Question

當我執行 ORDER BY id 時，此查詢非常有效，但是當我嘗試按 likes_count 排序時，我不斷收到重復的分頁結果。 我已經嘗試過 DISTINCT & GROUP BY，但它不起作用。

知道如何在不重復行的情況下按 likes_count 排序。

SELECT * FROM '<?php echo($data['t_pubs']); ?>'  WHERE 'status' = "active"

    AND 'target' = "publication"

    <?php if(empty($cp["is_admin"])): ?>
        <?php if(not_empty($data['user_id'])): ?>
            AND ('priv_wcs' = "everyone" OR  'user_id' = <?php echo($data['user_id']); ?> OR 'user_id' IN (SELECT 'following_id' FROM '<?php echo($data['t_conns']); ?>' WHERE 'follower_id' = <?php echo($data['user_id']); ?> AND 'status' = "active"))
        <?php else: ?>
            AND 'priv_wcs' = "everyone"
        <?php endif; ?>
    <?php endif; ?>

    <?php if(not_empty($data['keyword'])): ?>
        AND ('text' LIKE "%<?php echo($data['keyword']); ?>%"

        <?php if($data['htag']): ?>
            OR 'text' LIKE "%{#id:<?php echo($data['htag']); ?>#}%"
        <?php endif; ?>)
    <?php endif; ?>

    <?php if(not_empty($data['offset'])): ?>
        AND 'id' < <?php echo($data['offset']); ?>
    <?php endif; ?>

    <?php if(not_empty($data['user_id'])): ?>
        AND 'user_id' NOT IN (SELECT b1.'profile_id' FROM '<?php echo($data['t_blocks']); ?>' b1 WHERE b1.'user_id' = <?php echo($data['user_id']); ?>)

        AND 'user_id' NOT IN (SELECT b2.'user_id' FROM '<?php echo($data['t_blocks']); ?>' b2 WHERE b2.'profile_id' = <?php echo($data['user_id']); ?>)

        AND ('id' NOT IN (SELECT 'post_id' FROM '<?php echo($data['t_reports']); ?>' WHERE 'user_id' = <?php echo($data['user_id']); ?>))
    <?php endif; ?>

    ORDER BY 'likes_count' DESC, 'id' DESC

<?php if(is_posnum($data['limit'])): ?>
    LIMIT <?php echo($data['limit']); ?>;
<?php endif; ?> 

看起來像AND 'id' < <?php echo($data['offset']); ?>問題 AND 'id' < <?php echo($data['offset']); ?>當我從查詢 ORDER BY ID 中刪除它時，也會返回重復的行。 我試圖弄清楚如何更改AND 'id' < <?php echo($data['offset']); ?> AND 'id' < <?php echo($data['offset']); ?>使用 ORDER BY likes_count 防止重復行