如何每行從文本區域輸入行保存長文本

Question

如何從每行文本區域輸入行保存長文本我有一個帶有文本區域的表單，我想在 mysql 中每行保存一個長文本行我不知道

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Answer 1

您需要了解 mysql 如何與 DB 交互。 您可能需要使用 VARCHAR 數據類型，具體取決於您的文本區域有多大。 因此，如果來自 from 的字段最多 250 個字符，則文本區域列的數據類型將為 VARCHAR(250)。

您可以使用以下內容向文件發出 POST 請求：

$post = $_POST;
//set other fields here, I recommend sanitizing your inputs.
...
$textarea = $_POST['text_area'];
$servername = "HOST";   
$username = "username"; 
$password = "password";

// Create connection
$conn = new mysqli($servername, $username, $password);

// Check connection
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO MyGuests (...other columns you have, textarea)
       VALUES (..., $textarea)";

if ($conn->query($sql) === TRUE) {
   echo "New record created successfully";
} else {
   echo "Error: " . $sql . "<br>" . $conn->error;
}

我強烈建議查看兩個鏈接：
如何通過 php 過濾輸入（在 sql 執行之前使用）
PHP MySQL 插入數據

Answer 2

follow these steps to save any type of data in mysql using php

Step one

open xampp and run tomcat and mysql 

Step two 

now go to phpmyadmin and create a database mydatabase 
and create table named  posts and add fields id , title , description;

Datatypes for you columns

id = int  make it auto_increment and primary key !important
title = varchar(256)
description  = longtext

remember to select these datatypes in phpmyadmin

Step three

open your code editor make a file called posts.html and past 
the below code in your body section 

    <form action='post.php' method='post'>

    <div class="form-group">
    <label >Post title </label>
    <input type="text" name='title' class="form-control">
    </div>

    <div class="form-group">
    <label >Post Description</label>
    <textarea name='descp'  rows="3"></textarea>
    </div>

    <button type="submit" class="btn btn-primary">Submit</button>
    </form>

Step Four

now to handle the action you have to create a file post.php and past the blow code 



        <?php 
    $con = mysqli_connect('localhost' , 'root' , '' , 'mydatabase'); 
    if($_SERVER['REQUEST_METHOD'] == 'POST'){ 
        $title =   $_POST['title']; $descp =   $_POST['descp'];
         $query = "insert into posts(title , description) value($title , $descp)";
          $result = mysqli_query($con , $query);
           if($result){ echo 'data saved successfully'; }
           else{ echo "sorry their is an error please try again"; 
           } }
           ?>


Step five 

now open you phpmyadmin and go the database named mydatabase and open the table posts you fill find the record their which you have submitted now .

Answer 3

如果我查看您的表單數據會更容易。 我將假設我自己的表單數據來嘗試回答您的問題。
表格.php

            <form action="processing.php" method="POST">
                  <textarea required name="records" class="form-control" rows="8" cols="4" placeholder="Enter records separated by new line"></textarea>
              <button type="submit" name="addRecords" class="btn btn-warning">Add Records</button>
            </form>

然后加工.php

if (isset($_POST['addRecords'])) {
    $record = $_POST['records'];
    //explode records based on new line \n
    $records = explode("\n", $record);

    foreach ($records as $new) {
      $data = $new;
      //Here you'll write your sql code to insert records in the database
      
    }
  }