mysql：獲取達到目標的最短日期

Question

我希望這個描述是清楚的：

我有一個包含以下字段的表：

用戶身份	order_id	創建日期	分數	姓名
u.id_1	o.id_1	日期_1	0.0024	一些名字
u.id_2	o.id_2	日期_2	0.0053	一些名字

我想要另一個字段，它告訴我每個 user_id 是它獲得至少 0.05 個分數的最小日期。

我有這個查詢

SELECT r.user_id as user_id,
       r.id as order_id,
       r.created_at as creation_date,
       r.fraction as fractions,
       r.mining_name as name,
       SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) as growing_sum,
       CASE WHEN SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) >=0.05 THEN TRUE ELSE FALSE END AS isInClub500
FROM yield_mining_rent r
ORDER BY user_id, creation_date

它告訴我是否告訴我一個累積總和，以及我是否超過 0.5 個分數，但我也想要一個字段。

我知道如果我像這樣使用 CTE，我可以做到這一點：

WITH CTE AS (SELECT r.user_id                                                           as user_id,
                    r.id                                                                as order_id,
                    r.created_at                                                        as creation_date,
                    r.fraction                                                          as fractions,
                    r.mining_name                                                       as name,
                    SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) as growing_sum,
                    CASE
                        WHEN SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) >= 0.05 THEN TRUE
                        ELSE FALSE END                                                  AS isInClub500
             FROM yield_mining_rent r
             ORDER BY user_id, creation_date
)
SELECT user_id,
       min(creation_date)
FROM CTE
WHERE isInClub500 = true
GROUP BY user_id

但我的問題是：有沒有辦法在沒有 CTE 的情況下得到這個？ 太感謝了