在Python中使用二元运算符...翻译if（c1> =“\\ xc0”＆c1 <=“\\ xdf”）

Question

i am converting an external class from PHP to Python, it does some tricks like :

if ($c1 >= "\xc0" & $c1 <= "\xdf")
[...]
$cc1 = (chr(ord($c1) / 64) | "\xc0");
[...]
$cc2 = ($c1 & "\x3f") | "\x80";

where $c1,^$cc1, $cc2 are characters

and i just realized that i cannot use it as such with python, as characters are string, and not duplicately seen as "binary representation of a character" where operators & and | make sense...

please, how would you translate any of these in a Pythonic way ?

>>> c1 = "a"
>>> (c1 & "\x3f") | "\x80"

Traceback (most recent call last):
  File "<pyshell#202>", line 1, in <module>
    (c1 & "\x3f") | "\x80"
TypeError: unsupported operand type(s) for &: 'str' and 'str'

EDIT: actually, it seems that this PHP class do not work, so it will not fit my needs either. Many thanks for your help.

Answer 1

That's a primitive UTF-8 encoding function.

c1.encode('utf-8')

Note that unless you use unicode s natively (and why aren't you?) you'll need to decode from 'latin-1' first.

Answer 2

Use the ord function to get the value and then use actual numbers to do the masking.

>>> c1 = "a"
>>> (ord(c1) & 0x3f) | 0x80
161
>>> hex((ord(c1) & 0x3f) | 0x80)
'0xa1'

Answer 3

Python 2.7.3 (default, Sep 26 2012, 21:51:14) 
>>> c1 = 'd'
>>> # if ($c1 >= "\xc0" & $c1 <= "\xdf")
... 
>>> ord(c1) >= 0xc0 and ord(c1) <= 0xdf
False
>>> # $cc1 = (chr(ord($c1) / 64) | "\xc0");
... 
>>> chr(ord(c1) / 64 | 0xc0)
'\xc1'
>>> # $cc2 = ($c1 & "\x3f") | "\x80";
... 
>>> ord(c1) & 0x3f | 0x80
164
>>>