[英]Tracing back foreign-keys
I have the following tables: 我有以下表格:
class Person (models.Model):
GENDER_CHOICES = (
('M', 'Male'),
('F', 'Female'),
)
first_name = models.CharField(max_length=50)
last_name = models.CharField(max_length=50)
gender = models.CharField(max_length = 1, choices=GENDER_CHOICES, default='M')
age = models.IntegerField()
photo = models.ImageField(upload_to='uploads/images/runners', blank=True)
def __unicode__(self):
return '%s, %s' % (self.last_name, self.first_name)
and 和
class Runner (models.Model):
''' Represents a runner actually in a particular Race '''
position = models.IntegerField()
person = models.ForeignKey(Person, related_name="person")
race = models.ForeignKey(Race)
and 和
class Race (models.Model):
'''An instance of an Event. i.e., the race that is happening this year'''
year = models.IntegerField()
description = models.TextField()
event = models.ForeignKey(Event)
def leaderboard(self):
'''
Orders the leaders and returns the entire set
Args:
Returns:
A list of Runners ordered by position
'''
#board = Runner.objects.prefetch_related("person").filter(race=self).order_by('position')
board = Runner.objects.prefetch_related("person")
print "DEBUG: %s" % board.values()
return board
What I am trying to accomplish is to retrieve and subsequently encode a JSON response that contains a list of Runner instances with the attributes of each corresponding Person instance contained therein. 我要完成的工作是检索并随后编码一个JSON响应,其中包含一个Runner实例列表,其中包含每个对应的Person实例的属性。
In the leaderboard method, I have written an example of my Query. 在排行榜方法中,我编写了一个查询示例。 Upon executing it, I get the following:
执行后,我得到以下信息:
DEBUG: [{'person_id': 1, 'position': 1, 'id': 1, 'race_id': 1}, {'person_id': 2, 'position': 2, 'id': 2, 'race_id': 1}]
What I want that to look like is to have the QuerySet expand (and replace) each 'person_id" field with a Person instance and all the associated attributes of that instance. (ie, first_name, last_name, etc. 我想要的样子是让QuerySet用Person实例以及该实例的所有关联属性(即first_name,last_name等)扩展(并替换)每个“ person_id”字段。
Is this possible? 这可能吗? I've tried playing around with both prefetch_related() and select_related but to no avail.
我试过玩prefetch_related()和select_related,但无济于事。
As always, any help is much appreciated. 与往常一样,我们非常感谢您的帮助。
You can get all of the runners in a race by doing: 您可以通过以下方法使所有跑步者参加比赛:
self.runner_set.select_related('person')
This will contain all of the runners, and will have a JOIN
to the person table. 这将包含所有跑步者,并将对个人表具有
JOIN
。
When you use .values()
, then it gives you back the foreign key values, which is not what you want. 当您使用
.values()
,它将返回您不需要的外键值。
If you want, you can use the related_name="runners"
within your foreign key to Race. 如果需要,您可以在Race的外键中使用
related_name="runners"
。 Then you'll be able to access it via self.runners...
然后,您将可以通过
self.runners...
访问它self.runners...
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