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TypeError:“ int”对象不支持项目分配

[英]TypeError: 'int' object does not support item assignment

Why do I get this error? 为什么会出现此错误?

    a[k] = q % b
 TypeError: 'int' object does not support item assignment

Code: 码:

def algorithmone(n,b,a):
     assert(b > 1)
     q = n
     k = 0
     while q != 0:
        a[k] = q % b
        q = q / b
        ++k

     return k

print (algorithmone(5,233,676))
print (algorithmone(11,233,676))
print (algorithmone(3,1001,94))
print (algorithmone(111,1201,121))

You're passing an integer to your function as a . 你传递一个整数,以你的函数作为a You then try to assign to it as: a[k] = ... but that doesn't work since a is a scalar... 然后,您尝试将其分配为: a[k] = ...但这不起作用,因为a是标量...

It's the same thing as if you had tried: 就像您尝试过的一样:

50[42] = 7

That statement doesn't make much sense and python would yell at you the same way (presumably). 该语句没有多大意义,并且python会以相同的方式对您大喊大叫(大概)。

Also, ++k isn't doing what you think it does -- it's parsed as (+(+(k))) -- ie the bytcode is just UNARY_POSITIVE twice. 另外, ++k并没有按照您的想法去做-被解析为(+(+(k))) ,即字节码只是两次UNARY_POSITIVE What you actually want is something like k += 1 您实际想要的是类似k += 1

Finally, be careful with statements like: 最后,请注意以下语句:

q = q / b

The parenthesis you use with print imply that you want to use this on python3.x at some point. 与print一起使用的括号表示您想在某个时候在python3.x上使用它。 but, x/y behaves differently on python3.x than it does on python2.x. 但是, x/y在python3.x上的行为不同于在python2.x上的行为。 Looking at the algorithm, I'm guessing you want integer division (since you check q != 0 which would be hard to satisfy with floats). 看一下算法,我猜你想要整数除法 (因为检查q != 0 ,这对于浮点数很难满足)。 If that's the case, you should consider using: 如果是这样,您应该考虑使用:

q = q // b

which performs integer division on both python2.x and python3.x. 在python2.x和python3.x上执行整数除法。

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