jQuery / PHP-当由jQuery .ajax读取时，具有多个PHP块会产生额外的输出字符
[英]jQuery/PHP - Having more than one PHP block creates extra character of output when read by jQuery .ajax
问题描述
I've managed to boil this problem down to the bare essentials: So I've got two simple .php files: 
我设法将这个问题归结为基本要点：因此，我有两个简单的.php文件：
TEST.PHP test.php的
<!DOCTYPE html>
<html>
<head>
<meta charset='utf-8'>
<title>My Page</title>
<script src='/root/js/jquery-1.6.3.js'></script>
<script>
$(document).ready(function() {
$.ajax({
url : 'test_ajax.php',
type : 'GET',
timeout : 10000,
dataType : 'text',
data : { 'param' : 'whatever' },
success : function(data,status,jqXHR) {
$('#status').html(data.length+"-"+data);
},
error : function(jqXHR,textStatus,errorThrown) {
$('#status').html("Error: "+textStatus+" , "+errorThrown);
},
complete : function(jqXHR,textStatus) {
}
});
}); // end ready
</script>
</head>
<body>
<p id='status'>
</p>
</body>
</html>
and TEST_AJAX.PHP 和TEST_AJAX.PHP
<?php
?>
<?php
echo "ok";
?>
The data that should be returned from TEST_AJAX.PHP is "ok". 应该从TEST_AJAX.PHP返回的数据为“ ok”。 However, what is being retrieved by the jQuery/ajax code is a THREE character string which is outputted as " ok" (although the character at [0] is not equal to " "). 但是，由jQuery / ajax代码检索的是三个字符串，输出为“ ok”（尽管[0]处的字符不等于“”）。
This ONLY happens if I have the two php blocks in TEST_AJAX. 仅当我在TEST_AJAX中有两个php块时才会发生这种情况。 If I delete the first block, leaving only the second one, then it returns "ok" as a two character string, as it should. 如果删除第一个块，仅保留第二个块，那么它将按应有的那样以两个字符串的形式返回“ ok”。
What on earth is going on here? 这到底是怎么回事？ AFAIK, it should be perfectly acceptable to have multiple php blocks in a .php file - even though it's obviously unnecessary in this simplified example. AFAIK，.php文件中包含多个php块应该是完全可以接受的-尽管在此简化示例中显然没有必要。
4 个解决方案
解决方案1
4 2013-02-11 07:15:28
Note that there is a blank line between the two php blocks. 请注意，两个php块之间有一个空白行。 It also get's displayed. 它也得到显示。 Change it to 更改为
<?php
?><?php
echo "ok";
?>
and it should be fine. 而且应该没问题。
解决方案2
0 2013-02-11 07:18:12
I tried your code in my WAMP. 我在WAMP中尝试了您的代码。 You should remove spaces between PHP blocks: 您应该删除PHP块之间的空格：
<?php
?><?php
echo "ok";
?>
And more, You can use formatted results from server-side to client-side. 而且，您可以使用从服务器端到客户端的格式化结果。 Something like JSON , For example: 类似于JSON ，例如：
<!DOCTYPE html>
<html>
<head>
<meta charset='utf-8'>
<title>My Page</title>
<script src='jquery.js'></script>
<script>
$(document).ready(function() {
$.ajax({
url : 'test_ajax.php',
type : 'post',
timeout : 10000,
data : { 'param' : 'whatever' },
dataType: 'json',
success : function(data) {
alert(data.status);
}
});
}); // end ready
</script>
</head>
And in PHP: 在PHP中：
<?php
?>
<?php
echo json_encode(array("status"=>"ok"));
?>
As you can see in this approach, no matter how many spaces are between blocks. 如您所见，无论块之间有多少空格。
解决方案3
0 2013-02-11 07:20:59
White space in the PHP blocks is ignored, but the space between the PHP blocks will always be returned. PHP块中的空白将被忽略，但将始终返回PHP块之间的空白。 You may have better luck printing a json string like: 您可能会更好地打印json字符串，例如：
{'response':'ok'}
Then change your data type to json in your ajax request, and accessing the response with data.response 然后在ajax请求中将数据类型更改为json，并使用data.response访问响应
That way any extra spaces will not affect parsing 这样，任何多余的空格都不会影响解析
解决方案4
0 2013-02-11 07:21:27
PHP is a templating language. PHP是一种模板语言。 Everything outside of your tags will be not parsed and returned literally. 标签之外的所有内容都不会被解析并按字面值返回。
Example 例
<html>
..
<body>
<?php echo "Hello world";
// white space within the tags
?>
</body>
</html>
Will return 将返回
<html>
..
<body>
Hello world
</body>
</html>
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