[英]Set checkbox value from database in C# asp.net
I have 8 checkboxes
. 我有8个
checkboxes
。
On the page load
event I want to write the code such that 在
page load
事件中,我想编写如下代码
if the value
in the database
is "Submitted"
the checkbox
will appear checked
. 如果
database
的value
是"Submitted"
该checkbox
将显示为checked
。
If the value
is "Not Submitted"
it will appear unchecked
. 如果该
value
"Not Submitted"
,它将显示为unchecked
。
you can have something like this 你可以有这样的事情
if(!Page.IsPostBack)
{
var isChecked = dbvalue.ToLower() == "submitted" ? true : false;
for (var i = 0; i < 8;i++ )
{
CheckBox chk = (CheckBox)Form.FindControl("chk" + i);
if(chk != null) chk.checked = isChecked;
}
}
You can check the values like this 您可以检查像这样的值
if(!Page.IsPostBack)
{
if(dbvalue=="Submitted")
{
chk1.checked=true;
chk2.checked=true;
chk3.checked=true;
chk4.checked=true;
chk5.checked=true;
chk6.checked=true;
chk7.checked=true;
chk8.checked=true;
}
else if(dbvalue=="Not Submitted")
{
chk1.checked=false;
chk2.checked=false;
chk3.checked=false;
chk4.checked=false;
chk5.checked=false;
chk6.checked=false;
chk7.checked=false;
chk8.checked=false;
}
}
If don't want to do anything in the code-behind, a faster and easy method would be to create a new column of data type bit on the select query and then just bind the checkbox to that. 如果不想在后面的代码中做任何事情,那么一种更快,更简单的方法是在选择查询上创建一个数据类型为bit的新列,然后将复选框绑定到该列。 0 = false and 1 = true.
0 =假和1 =真。 Example would be:
例如:
SELECT
CAST((CASE WHEN SubmitColumn = 'Submitted' THEN
1
ELSE
0
END) AS BIT) AS chkValue
FROM Table_1
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