无法在XMPP聊天应用程序中注册用户

Question

I want to implement XMPP framework in my iOS App, I have completed all the things in (Chatting with other users , showing presence of other users , etc.)

But the problem is , I am unable to get the new user registered from my App. I am using following code for that,

if ([appDel.xmppStream supportsInBandRegistration])
    [appDel.xmppStream registerWithPassword:txt_Password.text error:nil];

But for this, supportsInBandRegistration method always returns NO and I dont get called the method never registerWithPassword: .

Help me if any solution available

Answer 1

What server are you using? Some servers support in-band registration even thought they don't send the correct stream:feature according to XEP-0077. Most of them should give the feature in the disco results however.

---- OR ---- You can solve this by following code. It's working fine for me. :

- (void)xmppStream:(XMPPStream *)sender didNotAuthenticate: 
(NSXMLElement *)error; 
{ 
NSLog(@"Did not authenticate"); 

 [xmppStream registerWithPassword:[[NSUserDefaults 
standardUserDefaults] stringForKey:@"userPassword"] error:nil]; 

NSError * err = nil; 

if(![[self xmppStream] registerWithPassword:password error:&err]) 
{ 
    NSLog(@"Error registering: %@", err); 
} 

} 
- (void)xmppStreamDidRegister:(XMPPStream *)sender{ 

NSLog(@"I'm in register method"); 

    } 

- (void)xmppStream:(XMPPStream *)sender didNotRegister:(NSXMLElement 
*)error{ 
NSLog(@"Sorry the registration is failed"); 

} 

I declare the registerWithPassword:error: method in didNotAuthenticate: method because after connection to the server it is going to this didNotAuthenticate method through where my registration methods is working fine

Answer 2

I had the same problem that [xmppStream supportsInBandRegistration] method was returning false because i was passing Jid that was already registered in the server.

[xmppStream setMyJID:[XMPPJID jidWithString:jabberID]];

changes JID worked for me.