根据NodeJS中的模式（xsd）验证XML

Question

Do any of the XML libraries in NPM support the validation of XML against an XSD schema?

I would look myself, but:

$ npm search xml 2>/dev/null | wc -l
212

Note: the xsd package is not what it seems and node-xerces is broken/empty.

Answer 1

Hij1nx (Paolo Fragomeni) pointed me at https://github.com/polotek/libxmljs

After half an hour of trying to figure out the API, I have a solution:

#!/usr/local/bin/node
var x = require('libxmljs');

var xsd = '<?xml version="1.0" encoding="utf-8" ?><xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://example.com/XMLSchema/1.0" targetNamespace="http://example.com/XMLSchema/1.0" elementFormDefault="qualified" attributeFormDefault="unqualified"><xs:element name="foo"></xs:element></xs:schema>'
var xsdDoc = x.parseXmlString(xsd);

var xml0 = '<?xml version="1.0" encoding="UTF-8"?><foo xmlns="http://example.com/XMLSchema/1.0"></foo>';
var xmlDoc0 = x.parseXmlString(xml0);
var xml1 = '<?xml version="1.0" encoding="UTF-8"?><bar xmlns="http://example.com/XMLSchema/1.0"></bar>';
var xmlDoc1 = x.parseXmlString(xml1);

var result0 = xmlDoc0.validate(xsdDoc);
console.log("result0:", result0);

var result1 = xmlDoc1.validate(xsdDoc);
console.log("result1:", result1);

This produces the output:

result0: true
result1: false

I have no idea whether/how this will work with schemas which reference other schemas via URIs.