通过正则表达式获取列表中字典项的索引

Question

I have a list:

[
  {
    'avail': 'blabla',
    'rep_main': 'qweqwe',
    ....
  },
  {
    'avail': 'asdasd',
    'rep_main': 'zxczxc',
    ....
  },
  ...
]

I want to get the index of the item by means of regexp That's like a version without regexp:

[list['rep_main'] for elem in list].index('qweqwe')

Answer 1

If pattern is the pattern and re is the re module :

[i for i, elem in enumerate(mylist) if re.match(pattern, elem['rep_main'])]

You can use re.search instead of re.match .

enumerate is a convenient built-in function that lets you use indexes without that for i in range(len(mylist)) ugliness.

Note: the expression above obviously evaluates to a list. .index() method returns the first matching index. To achieve that, write:

next(i for i, elem in enumerate(mylist) if re.match(pattern, elem['rep_main']))