[英]Create generic List<T> with reflection
I have a class with a property IEnumerable<T>
.我有一个属性
IEnumerable<T>
。 How do I make a generic method that creates a new List<T>
and assigns that property?如何创建一个创建新
List<T>
并分配该属性的通用方法?
IList list = property.PropertyType.GetGenericTypeDefinition()
.MakeGenericType(property.PropertyType.GetGenericArguments())
.GetConstructor(Type.EmptyTypes);
I dont know where is T
type can be anything我不知道
T
型在哪里可以是任何东西
Assuming you know the property name, and you know it is an IEnumerable<T>
then this function will set it to a list of corresponding type:假设您知道属性名称,并且您知道它是一个
IEnumerable<T>
那么此函数会将其设置为相应类型的列表:
public void AssignListProperty(Object obj, String propName)
{
var prop = obj.GetType().GetProperty(propName);
var listType = typeof(List<>);
var genericArgs = prop.PropertyType.GetGenericArguments();
var concreteType = listType.MakeGenericType(genericArgs);
var newList = Activator.CreateInstance(concreteType);
prop.SetValue(obj, newList);
}
Please note this method does no type checking, or error handling.请注意,此方法不进行类型检查或错误处理。 I leave that as an exercise to the user.
我把它留给用户作为练习。
using System;
using System.Collections.Generic;
namespace ConsoleApplication16
{
class Program
{
static IEnumerable<int> Func()
{
yield return 1;
yield return 2;
yield return 3;
}
static List<int> MakeList()
{
return (List<int>)Activator.CreateInstance(typeof(List<int>), Func());
}
static void Main(string[] args)
{
foreach(int i in MakeList())
{
Console.WriteLine(i);
}
}
}
}
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