警告在初始化C字符串数组时从字符串const转换为char *

Question

I used to do the following to declare and initialize an array of string in C:

char *myTable[] = {
   "ABC",  "Y", "*",  "*",
   "WXYZ", "Y", "*",  "*",
   "MNO",  "Y", "*",  "*",
   NULL,   NULL,NULL, NULL
};

The NULL's are for internal use.

Since I moved to gcc 4.4.6, I get a warning:

abc.cpp:74: warning: deprecated conversion from string constant to ‘char*’

What is the correct way of initializing my array ?

Answer 1

It's because you're trying to drop off the constness of these string literals and compiler is considerate enough to warn you about it since trying to modify the memory where these constant string literals are stored leads to undefined behaviour [1]

Declare your array as const char *myTable[]

---

[1]: C99 Standard: 6.7.8 Initialization §32 :

the declaration char *p = "abc"; defines p with type ''pointer to char '' and initializes it to point to an object with type ''array of char '' with length 4 whose elements are initialized with a character string literal. If an attempt is made to use p to modify the contents of the array, the behavior is undefined.

Answer 2

尝试使用const char *而不是char* 。

Answer 3

这是因为字符串文字是常量，所以您必须使用const char *myTable[] 。

Answer 4

a string that looks like "hello world" is an immutable string constant. You must declare

const char *myTable[] = {
   "ABC",  "Y", "*",  "*",
   "WXYZ", "Y", "*",  "*",
   "MNO",  "Y", "*",  "*",
   NULL,   NULL,NULL, NULL
};