[英]How to continuously rotate children in a jQuery animation?
I have a div with class 'bannergroup' that contains multiple divs 'banneritem'. 我有一个带有'bannergroup'类的div,它包含多个div'banneritem'。 I want these items to rotate (fade in then fade out) in place of each other. 我希望这些项目能够旋转(淡入然后淡出)代替彼此。
I can have several divs with the class bannergroup and each one should rotate separately. 我可以使用类bannergroup有几个div,每个div应该单独旋转。
Here is the HTML: 这是HTML:
<div class="bannergroup">
<div class="banneritem">Only visible one at a time</div>
<div class="banneritem">Only visible one at a time</div>
<div class="banneritem">Only visible one at a time</div>
<div class="banneritem">Only visible one at a time</div>
</div>
<div class="bannergroup">
<div class="banneritem">Only visible one at a time</div>
<div class="banneritem">Only visible one at a time</div>
<div class="banneritem">Only visible one at a time</div>
<div class="banneritem">Only visible one at a time</div>
</div>
My Jquery looks like: 我的Jquery看起来像:
$('.banneritem').css('display', 'none');
$('.bannergroup').children('.banneritem').each(function( i ) {
$(this).fadeIn().delay(4000).fadeOut();
});
The problem: the each statement continues to run before the previous div completes. 问题:每个语句在前一个div完成之前继续运行。 I want it to wait until the previous child is gone. 我希望它等到上一个孩子不见了。 Also, I need this to continuously run. 此外,我需要这个继续运行。 After a single time it stops. 一次后它停止。 I can put this into a function, but I am not sure how to know to call it again. 我可以把它放到一个函数中,但我不知道怎么知道再次调用它。
EDIT : There are not always 4 child items. 编辑 :并不总是4个子项目。 Also one group may have a different number of children than the others, but they should both rotate in-sync. 另外一组可能具有与其他组不同的子组数,但它们应该同步旋转。 It is ok if one completes before the other and then just restarts itself. 如果一个在另一个之前完成然后重新启动它就可以了。
I have answered this question multiple times before. 我已经回答了这个问题多 的时间了。 This time I will try wrapping it in a jQuery plugin. 这次我将尝试将其包装在jQuery插件中。 The .rotate()
function will apply the effect you want to the children of the matched elements, a fade in/out effect per children in a continuous animation. .rotate()
函数将您想要的效果应用于匹配元素的子元素,即连续动画中每个子元素的淡入/淡出效果。
$.fn.rotate = function(){
return this.each(function() {
/* Cache element's children */
var $children = $(this).children();
/* Current element to display */
var position = -1;
/* IIFE */
!function loop() {
/* Get next element's position.
* Restarting from first children after the last one.
*/
position = (position + 1) % $children.length;
/* Fade element */
$children.eq(position).fadeIn(1000).delay(1000).fadeOut(1000, loop);
}();
});
};
Usage: 用法:
$(function(){
$(".banneritem").hide();
$(".bannergroup").rotate();
});
$('div.bannergroup').each(function () {
$('div.banneritem', this).not(':first').hide();
var thisDiv = this;
setInterval(function () {
var idx = $('div.banneritem', thisDiv).index($('div.banneritem', thisDiv).filter(':visible'));
$('div.banneritem:eq(' + idx + ')', thisDiv).fadeOut(function () {
idx++;
if (idx == ($('div.banneritem', thisDiv).length)) idx = 0;
$('div.banneritem', thisDiv).eq(idx).fadeIn();
});
}, 2000);
});
You can solve this problem in 2 ways. 您可以通过两种方式解决此问题。 The one below is the easiest, using the index to increase the delay per item. 下面的一个是最简单的,使用索引来增加每个项目的延迟。
$('.banneritem').css('display', 'none');
$('.bannergroup').children('.banneritem').each(function( i ) {
$(this).delay(4000 * i)).fadeIn().delay(4000 * (i+1)).fadeOut();
});
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