从XML文件中提取特定节点

Question

I want to read a section from the XML file below with C#.

 <?xml version="1.0" encoding="utf-8" > 
 <DataSet>
 <xs:schema id="NewDataSet" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
 <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
 <xs:complexType>
 <xs:choice minOccurs="0" maxOccurs="unbounded">
 <xs:element name="Table">
 <xs:complexType>
 <xs:sequence>
  <xs:element name="Column1" type="xs:string" minOccurs="0" /> 
  </xs:sequence>
  </xs:complexType>
  </xs:element>
  </xs:choice>
  </xs:complexType>
  </xs:element>
  </xs:schema>
 <diffgr:diffgram xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
 <NewDataSet>
 <Table diffgr:id="Table1" msdata:rowOrder="0">
  <Column1><Properties><Property>.....

I want to extract the nodes below the Column1 nodes. The Properties node has lots of Property nodes, so I want the Properties node with all the Property nodes.

Please let me know the easiest and efficient way to get the nodes in C#.

Answer 1

You can use an Linq-to-XML classes to parse the string and then XPath expression to select the nodes that you want:

XElement doc = XElement.Parse(s); //where s is a string containing the XML
var properties = doc.XPathSelectElements("//Column1/Properties");

Now properties contains a enumerable of the nodes that you want.

If you want to iterate through all the Property nodes you can do so like this:

foreach(var pp in properties)
{
    foreach(var p in pp.Elements("Property"))
    {
         //do something
    }
}