NSIS - 如何获取安装程序可执行文件的文件名？

Question

I've found two ways of getting the complete path of the installer file in a NSIS script:

1. System::Call 'kernel32::GetModuleFileNameA(i 0, t .R0, i 1024) i r1'
2. Using $EXEPATH (2.26+)

But I need only the filename, and not the complete path. How go get it? Is there an ExtractFileName() type function?

Answer 1

$EXEFILE is what you want. It'll be of the form foo.exe .