[英]Passing parameters using url scheme
I am working on a app which could be launched over a URL. 我正在开发一个可以通过URL启动的应用程序。 I have already defined my url scheme using xcode on info page.
我已经在信息页面上使用xcode定义了我的网址方案。 I filled for identifier my Bundle identifier and for URL Schemes myapp.
我填写了标识符我的Bundle标识符和URL Schemes myapp。
Now if I try to open in safari myapp://foo, it launches my app and stops at my breakpoint in 现在,如果我尝试在safari myapp:// foo中打开,它会启动我的应用程序并在我的断点处停止
- (BOOL)application:(UIApplication *)application
openURL:(NSURL *)url
sourceApplication:(NSString *)sourceApplication
annotation:(id)annotation
method. 方法。
Problem is annotation, url, application, sourceapplication parameters are nil. 问题是注释,url,应用程序,sourceapplication参数都是nil。 So I can not pass parameters...
所以我不能传递参数......
After unnecessary time loss, I have found out, the problem was the debugger. 在不必要的时间丢失之后,我发现问题是调试器。 It shows the url is nil and if I try to print description it says
它显示网址是零,如果我尝试打印说明它说
Printing description of url:
<nil>
But If I try to NSLog it shows the url. 但如果我尝试NSLog,它会显示网址。 And if put the following code in the method
如果在方法中放入以下代码
if (! url) {
return NO;
}
The debugger shows also the url. 调试器还显示url。
Are you sure your project is in debug mode!? 你确定你的项目处于调试模式!? See here http://nerdwa.com/index.php/2011/09/debugrelease-schemes-in-xcode-4/
请参见http://nerdwa.com/index.php/2011/09/debugrelease-schemes-in-xcode-4/
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