Java文字游戏解析器问题

Question

This is my first post, and I'm only new to Java, so sorry if it is not up to scratch.

I have been writing a text-based adventure game in Java, and my code has failed me in one place - the parser. There is no error, it just doesnt work. It takes in the input but does nothing about it. It is very simple, and looks something like this:

public static void getInput(){
    System.out.print(">>"); //print cue for input
    String i = scan.nextLine(); //get (i)nput
    String[] w = i.split(" "); //split input into (w)ords
    List words = Arrays.asList(w); //change to list format
    test(words);
}

The test method just searches the list for certain words using if(words.contains("<word>")) .

What is wrong with the code and how can I improve it?

Answer 1

How about keeping the array and using something like this:

    String[] word_list = {"This","is","an","Array"}; //An Array in your fault its 'w'
for (int i = 0;i < word_list.length;i++) { //Running trough all Elements 
    System.out.println(word_list[i]);
            if (word_list[i].equalsIgnoreCase("This")) {
        System.out.println("This found!");
    }
    if (word_list[i].equalsIgnoreCase("is")) {
        System.out.println("is found!");
    }
    if (word_list[i].equalsIgnoreCase("an")) {
        System.out.println("an found!");
    }
    if (word_list[i].equalsIgnoreCase("Array")) {
        System.out.println("Array found!");
    }
    if (word_list[i].equalsIgnoreCase("NotExistant")) { //Wont be found
        System.out.println("NotExistant found!"); 
    }
}

You will get the following output:

This found!
is found!
an found!
Array found!

As you can see you needn't convert it to a List at all!

Answer 2

Here is how I would do this:

public class ReadInput {
    private static void processInput (List <String> words)
    {
        if (words.contains ("foo"))
            System.out.println ("Foo!");
        else if (words.contains ("bar"))
            System.out.println ("Bar!");
    }

    public static void readInput () throws Exception
    {
        BufferedReader reader = 
            new BufferedReader (
                new InputStreamReader (System.in));

        String line;
        while ((line = reader.readLine ()) != null)
        {
            String [] words = line.split (" ");
            processInput (Arrays.asList (words));
        }
    }

    public static void main (String [] args) throws Exception 
    {
        readInput ();
    }
}

Sample session:

[in]  hello world
[in]  foo bar
[out] Foo!
[in]  foobar bar foobar
[out] Bar!