为什么我会得到ELIF无效的语法？

Question

I cant see anything wrong with the following code :

    elif choice == "2":
    while True:
        PhoneSearch = raw_input("What is their telephone number? : ")
        conn = sqlite3.connect('SADS.db')
        cur = conn.cursor()
        cur.execute("SELECT * FROM customers WHERE Telephone = (?)",(PhoneSearch,))
        row = cur.fetchone()
        if row:
            CustID = row[0]
            print "|------------------------------------------|"
            print "|Customer ID : " , row[0]
            print "|Forename : " , row[1]
            print "|Surname : " , row[2]
            print "|Address Line 1 : " , row[3]
            print "|Address Line 2 : " , row[4]
            print "|City : " , row[5]
            print "|Postcode : " , row[6]
            print "|Telephone number : " , row[7]
            print "|E-Mail : " , row[8]
            while True:
                print '|Do you want to see what seats', row[1]
                choice = raw_input("|Choice Y/N:")
                if choice == 'Y':
                    cur.execute("SELECT * FROM seats WHERE CustID = (?)", (CustID,))
                    rowseat = cur.fetchone()
                    if rowseat: # or if rowseat is not None, etc.
                        print "|Seats booked:" , rowseat[0]
                        print "|------------------------------------------|"
                        break
                    else:
                        print("database doesn't have correct info")
            else:
                print("Na")

Yet i get a syntax error on the Elif statement at the top. Please tell me why this is happening or where the error is?

Answer 1

Python expects an indented block after your elif statement, same as for an if , while or else statement. In your example, everything after elif should be indented.

Answer 2

Indent everything under the elif to include it in the things to do if the elif is correct. At the moment it is meaning:

elif choice == "2":
     pass  # nothing here
while True:
     PhoneSearch = raw_input("What is their telephone number? : ")
     # etc

so it isn't finding anything to do if it is correct and will do the while anyway. If this is what you wish to do, you can put "pass" (minus the "") in the place of ##nothing here