仅按月份和年份分组日期

Question

Assuming I have a table like the following:

id | assignment | duedate
1  | Math       | 2012-01-01
2  | History    | 2012-02-02
3  | Science    | 2012-01-01
4  | Government | 2012-02-01
5  | Government | 2013-01-13
6  | History    | 2013-03-13

Is it possible to make some sql query such that I get a grouping of all the dates by month and year? Is there some possibility that I could get a sorted result of:

duedatemonth  | count 
January 2012  | 2
Feburary 2012 | 2
January 2013  | 1
March 2013    | 1

I know you can GROUP BY duedate, but that only groups those with the same month, day, and year instead of just month and year.

Would it be then possible to even further group it such that it factors in "assignment" to obtain a resulting table of

id | duedatemonth  | count 
1  | January 2012  | 2
3  | January 2012  | 2
2  | Feburary 2012 | 2
4  | Feburary 2012 | 2
5  | January 2013  | 1
6  | March 2013    | 1

Answer 1

Use the string functions YEAR and MONTH .

SELECT YEAR(duedate), MONTH(duedate), COUNT(*)
FROM sparkles
GROUP BY YEAR(duedate), MONTH(duedate)

Use MONTHNAME or DATE_FORMAT to get the name of the month.

Answer 2

You can use this query.

SELECT DATE_FORMAT(duedate, '%M %Y') duedatemonth, COUNT(1) `count`
FROM Tbl
GROUP BY DATE_FORMAT(duedate, '%M %Y')

Answer 3

try this

    SELECT DATE_FORMAT(duedate,'%M %Y')  duedatemonth, COUNT(*) count
    FROM Table1
   GROUP BY year(duedate), MONTH(duedate)

DEMO HERE

will output this:

   DUEDATEMONTH     COUNT
   January 2012     2
  February 2012     2
   January 2013     1
     March 2013     1