如何从XLL函数返回数组

Question

I am new in writing XLL, Anyone knows how to return a 6x1 array to Excel ?

The following is my function (some codes came from other post):

__declspec(dllexport) LPXLOPER12  WINAPI GetArr(char* arg1, char* arg2)
{
   vector<double> arr = functionReturnVector;

   XLOPER12 list;
   list.xltype = xltypeMulti | xlbitDLLFree;
   list.val.array.lparray = new XLOPER12[6];
   list.val.array.rows = 6;
   list.val.array.columns = 1;
   for(int i = 0; i < 6; ++i) {
      list.val.array.lparray[i] = arr[i]; // error: IntelliSense: no operator "=" matches these operands
   }
return &list;
}

[2013-02-23] Currently I read the codes from XLL RETURN ARRAY and review my code, it can compile but returns 0 ...

__declspec(dllexport) LPXLOPER12 WINAPI GetArr(void)
{   
XLOPER xlArray, xlValues[2];

xlValues[0].xltype = xltypeNum;
xlValues[1].xltype = xltypeNum;
xlValues[0].val.num = 11;
xlValues[1].val.num = 17;

xlArray.xltype = xltypeMulti|xlbitDLLFree;
xlArray.val.array.rows = 1;
xlArray.val.array.columns = 2;
xlArray.val.array.lparray = &xlValues;

return &xlArray;
} 

Answer 1

I can print an 1X2 array in Excel worksheet now, the following is my code.

**use Func signature type U

1.select one row and two columns

2.Type command =GetArray() in first cell

3.Ctrl + shift + enter

 __declspec(dllexport) LPXLOPER12 WINAPI GetArray(void)
{
    static XLOPER12 xlArray;
    XLOPER12 xlValues[2];
    xlValues[0].xltype = xltypeNum;
    xlValues[1].xltype = xltypeNum;
    xlValues[0].val.num = 123;
    xlValues[1].val.num = 456;
    xlArray.xltype = xltypeMulti|xlbitDLLFree;
    xlArray.val.array.rows = 1;
    xlArray.val.array.columns = 2;
    xlArray.val.array.lparray = &xlValues;
    return (LPXLOPER12)&xlArray;
}

Answer 2

Maybe http://xll.codplex.com can help you solve your problem, but as other people that are trying to help you, your code seems pretty far from shore.

On ne découvre pas de terre nouvelle sans consentir à perdre de vue, d'abord et longtemps, tout rivage.

Just kidding. Maybe that will work for you.