Android：如何通过单击视图弹出窗口？

Question

Here if that image is clicked, it opens a new window. How to achieve this? Its not a Menu right??

Answer 1

You can set an onClickListener on the ImageView like

mImageView.setOnClickListener(new View.OnClickListener() {
                            public void onClick(View v) {

                             // start a dialog

                            }
                        });

On click, you open a dialog http://developer.android.com/guide/topics/ui/dialogs.html .

Answer 2

View 's can trigger the onClick(View v) callback if you set the OnClickListener upon them. When the callback is invoked, you can simply switch trough View.getId(), in order to understand which View has been clicked. If the view 's clicked is the right one, instantiate and show your dialog.

Answer 3

try like this.

mImageView.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {

                AlertDialog.Builder builder = new AlertDialog.Builder(
                        ctContext);
                builder.setItems(listdatatopopulate,
                        new DialogInterface.OnClickListener() {
                            public void onClick(
                                    DialogInterface dialogInterface,
                                    int item) {
                                // do some thing on item click
                            }
                        });
                builder.create().show();

            }
        });

Answer 4

1. OnCreate you need this.registerForContextMenu(mImageView);

2. use onClickListener for mImageView :

    mImageView.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { v.performLongClick(); } }); 

3. Implement the context menu http://developer.android.com/guide/topics/ui/menus.html#context-menu