泛型-类型参数声明必须是标识符而不是类型

Question

On the first line, I get this compilation error. "Type parameter declaration must be an identifier not a type.". Is there a way to fix this?

 public class ExtJsGridJsonModel<IEnumerable<T>>
{
    [DataMember(Name = "total")]
    public int Total { get; set; }

    [DataMember(Name = "rows")]
    public IEnumerable<T> Rows { set; get; }

    public ExtJsGridJsonModel(IEnumerable<T> rows, int total)
    {
        this.Rows = rows;
        this.Total = total;
    }
}

Update:

Sorry for the lack of detail in my question and intentions. Basically, my end goal is to do this:

new ExtJsGridJsonModel<Company>();

rather than this:

new ExtJsGridJsonModel<IEnumerable<Company>>();

Basically, I want to reduce code by omitting the IEnumerable type. How do i do this?

Answer 1

Just take out the IEnumerable part of your declaration:

public class ExtJsGridJsonModel<T>
{
    [DataMember(Name = "total")]
    public int Total { get; set; }

    [DataMember(Name = "rows")]
    public IEnumerable<T> Rows { set; get; }

    public ExtJsGridJsonModel(IEnumerable<T> rows, int total)
    {
        this.Rows = rows;
        this.Total = total;
    }
}

Answer 2

I assume that you would be using this to store what is essentially a two dimensional set of values:

public class ExtJsGridJsonModel<T> where T : IEnumerable
{
    [DataMember(Name = "total")]
    public int Total { get; set; }

    [DataMember(Name = "rows")]
    public IEnumerable<T> Rows { set; get; }

    public ExtJsGridJsonModel(IEnumerable<T> rows, int total)
    {
        this.Rows = rows;
        this.Total = total;
    }
}

If not, or T is actually a strongly-typed row class, then you can remove the where T : IEnumerable clause