指尖替换包含方括号的字符串

Question

I have a string like this: [name-123456] .

I am attempting to replace the match of this string with some predefined strings. Here is what I have so far:

preg_replace('~\['.$string_to_be_replaced.'\]~', $code_to_replace_it_with, $content);

Currently this throws an error, I couldn't find out how to remove the square brackets (even though they are part of the string). How do I make sure those get removed in a regex so that [name-123456] gets replaced with stringofcode ?

EDIT:

$string_to_be_replaced = preg_quote($string_to_be_replaced, "~"); 
$content = preg_replace('~\['.$string_to_be_replaced.'\]~', $str_to_replace_with, $content);

this simply returns [name-123456] :p

A vardump produces: string(16) "\\[name\\-123456\\]"

Answer 1

Your first problem is likely that you didn't assign the result back:

$content = preg_replace('~...~', $rpl.., $content);

Then you should also escape the $string_to_be_replaced using preg_quote beforehand. It's necessary for the - in your search string anyway.

$string_to_be_replaced = preg_quote($string_to_be_replaced, "~");

Would also take care of the [ square ] brackets, btw.

And if you're not doing any assertions or complex matching, str_replace() might be an alternative.