[英]Shortcut to generate an NSRange for entire length of NSString?
Is there a short way to say "entire string" rather than typing out:有没有一种简短的方法可以说“整个字符串”而不是输入:
NSMakeRange(0, myString.length)]
It seems silly that the longest part of this kind of code is the least important (because I usually want to search/replace within entire string)…这种代码中最长的部分是最不重要的,这似乎很愚蠢(因为我通常想在整个字符串中搜索/替换)......
[myString replaceOccurrencesOfString:@"replace_me"
withString:replacementString
options:NSCaseInsensitiveSearch
range:NSMakeRange(0, myString.length)];
Function?功能? Category method?
分类方法?
- (NSRange)fullRange
{
return (NSRange){0, [self length]};
}
[myString replaceOccurrencesOfString:@"replace_me"
withString:replacementString
options:NSCaseInsensitiveSearch
range:[myString fullRange]];
Not that I know of.从来没听说过。 But you could easily add an
NSString
category:但是您可以轻松添加
NSString
类别:
@interface NSString (MyRangeExtensions)
- (NSRange)fullRange
@end
@implementation NSString (MyRangeExtensions)
- (NSRange)fullRange {
return (NSRange){0, self.length};
}
Swift 4+ , useful for NSRegularExpression
and NSAttributedString
Swift 4+ ,对
NSRegularExpression
和NSAttributedString
有用
extension String {
var nsRange : NSRange {
return NSRange(self.startIndex..., in: self)
}
func range(from nsRange: NSRange) -> Range<String.Index>? {
return Range(nsRange, in: self)
}
}
NSMakeRange(0, str.length)
or as an extension
:或作为
extension
:
extension NSString {
func fullrange() -> NSRange {
return NSMakeRange(0, self.length)
}
}
这不是更短,而是......哦,好吧
NSRange range = [str rangeOfString:str];
extension String {
var fullRange:Range<String.Index> { return startIndex..<endIndex }
}
as in如
let swiftRange = "abc".fullRange
or要么
let nsRange = "abc".fullRange.toRange
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