查找具有特定名称的所有子文件夹，以便超级文件夹具有特定模式
[英]finding all subfolder with certain name such that superfolder has certain pattern
问题描述
hi all I have a folder that has folders with lots of different names. 
大家好我有一个文件夹，其中包含许多不同名称的文件夹。 However I want to find all the folder that start with RUN and have a subfolder of complete . 但是我想找到所有以RUN开头并且子文件夹complete的文件夹。 How can I do such a thing in terminal? 我怎么能在终端做这样的事情？
1 个解决方案
解决方案1
2 已采纳 2013-02-25 16:13:15
As Mac OS X is UNIX based you can use many terminal programs found on Linux etc. too. 由于Mac OS X是基于UNIX的，因此您也可以使用Linux等上的许多终端程序。 Therefore this question is not necessarily OS X related. 因此，这个问题不一定与OS X有关。
Using find you can get all your RUN folders with a complete folder in it: 使用find您可以获得包含complete文件夹的所有RUN文件夹：
find path_to_your_folder/Run*/complete -maxdepth 0
This gives you a list like 这给你一个像这样的列表
path_to_your_folder/Run3221/complete
path_to_your_folder/Run3289/complete
With ´sed´ you can extract from this the individual folder names: 使用'had'，您可以从中提取单个文件夹名称：
find test/Run*/complete -maxdepth 0 | sed 's/.*\(Run[0-9]*\).*/\1/'
which gives you a list like you're looking for: 它给你一个像你正在寻找的列表：
Run3221
Run3289
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