简体   繁体   English

选择一个表中只有一个值的行

[英]Select a row with just one value in a table

This is my table looks: 这是我的表看起来:

(I don't say it before, colum2 is string type, not an integer, sorry about it) (我之前没有说过,colum2是字符串类型,不是整数,对不起)

╔══════╦═══════╗
║ USER ║ COLOR ║
╠══════╬═══════╣
║ a    ║ Red   ║
║ b    ║ Blue  ║
║ c    ║ Blue  ║
║ b    ║ Red   ║
║ a    ║ Red   ║
║ c    ║ White ║
╚══════╩═══════╝

I've just need the rows which has exclusively color= "Red". 我只需要具有专门的颜色行=“红”。
It must return "a" ("b" contains value "Blue" too). 它必须返回“a”(“b”也包含值“Blue”)。

How can I set the select? 如何设置选择? Thanks and regards 谢谢并恭祝安康

SELECT  column1
FROM    TableName
GROUP   BY Column1
HAVING  COUNT(DISTINCT column2) = 1
        AND MAX(column2) = 1

here's another way, 这是另一种方式,

SELECT  column1
FROM    TableName
GROUP   BY Column1
HAVING  MAX(column2) = MIN(column2) AND
        MAX(column2) = 1

UPDATE 1 更新1

SELECT  user
FROM    TableName
GROUP   BY user
HAVING  SUM(color = 'red') = COUNT(*)

The more efficient way to do this is by comparing the min and max values: 更有效的方法是比较minmax

select column1
from t
group by column1
having min(column2) = max(column2) and min(column2) = 1

If the column can take on NULL values, you will need to exclude those as well: 如果列可以采用NULL值,则还需要排除这些值:

select column1
from t
group by column1
having min(column2) = max(column2) and min(column2) = 1 and count(column2) = count(*)
Select distinct Column1 from Table1 Where Column2='1'

Or if it is integer then: 或者,如果它是整数,那么:

Select distinct Column1 from Table1 Where Column2=1

Assuming that Table1 is the table name 假设Table1是表名

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM