[英]Is this function with atomic thread-safe
I am trying to learn how to use atomic :) 我正在尝试学习如何使用原子:)
class foo {
static std::atomic<uint32_t> count_;
uint32 increase_and_get() {
uint32 t = count_++;
return t;
}
}
Is the function increase_and_get()
thread-safe? 函数
increase_and_get()
线程安全的吗?
Yes, it is safe: the increment is atomic, and the local t
cannot be altered by concurrent threads. 是的,这很安全:增量是原子的,并且本地
t
不能被并发线程更改。 You can further simplify your code to eliminate the temporary variable altogether: 您可以进一步简化代码,以完全消除临时变量:
uint32 increase_and_get() {
return count_++;
}
Yes, it would be threadsafe. 是的,这将是线程安全的。 Assuming of course there are no bugs in the
std::atomic
implementation - but it's not usually hard to get right. 假设在
std::atomic
实现中当然没有错误-但是通常不难正确。
This is exactly what std::atomic
is meant to do. 这正是
std::atomic
要做的。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.