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sql-从一列中查找值以从另一列中查找所有其他值

[英]sql - find value from a column to find all other values from another column

This is a SQL question, I will try my best to explain. 这是一个SQL问题,我将尽力解释。

I have a table like the following below 我下面有一张桌子

id  name    accounts
1   Jim 7001
1   Jim 7002
1   Jim 7003
2   Ryan    7001
3   Todd    7001
3   Todd    7003
2   Ryan    7002
4   Cam 7001
5   Fran    7001
2   Ryan    7003
1   Jim 7004

I am first trying to find all values with accounts column of '7001' to find the correct id's. 我首先尝试使用“ 7001”的“帐户”列查找所有值,以查找正确的ID。 After that I need to only pull the lines with those id's so I can see all the accounts for those specific ids. 之后,我只需要拉出带有这些ID的行,这样我就可以看到这些特定ID的所有帐户。

example code I am using 我正在使用的示例代码

select 
s.id,
s.name,
s.account

from 
students s

where
s.account in ('7001','7002','7003','7004')

I can do this with 2 queries one to find id's with '7001' account value and then run another query just for id's but would like to know if there is a way to write in order to have it all calculate in one shot. 我可以使用2个查询来执行此操作,一个查询找到具有“ 7001”帐户值的ID,然后运行另一个仅查询ID的查询,但想知道是否有一种写方法,以便一次计算所有的ID。

Thanks in advance! 提前致谢!

SELECT  *
FROM    tableName
WHERE   ID IN 
        (
            SELECT ID 
            FROM   tableName
            WHERE  accounts = 7001
        )

The JOIN version ( recommended ) JOIN版本( 推荐

SELECT  a.*
FROM    students a
        INNER JOIN students b
          ON a.ID = b.ID
WHERE   b.accounts = 7001
select t2.*
from tbl t1, tbl t2
where t1.accounts = '7001'
and t1.id = t2.id

This solution is optimized: 该解决方案经过优化:

SELECT  a.*
FROM    tableName as a
INNER JOIN tableName as b
    ON a.id = b.id
    AND b.accounts = 7001

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