SQL Server 2008中的圆形函数

Question

i have a query which rounds the value for the particular column name:

  select round([CIMtrek_CI_Act],0) as CI FROM [CIMtrek_SystemTable_DatawareHouse]

where [CIMtrek_CI_Act_33] is not null and CIMtrek_CIMtrekUniqueID = 1917

and the reulst is

CI
1

but when i execute the following query :

(SELECT  (SELECT [T1].[CIMtrek_CIMtrekUniqueID]  AS [CIMtrek_CIMtrekUniqueID]
,round([T1].[CIMtrek_CI_Act],0)   AS [CIMtrek_CI_Act]
 FROM [CIMtrek_SystemTable_DatawareHouse] T1 
 WHERE T1.CIMtrek_CIMtrekUniqueID = 1917 
 FOR  XML PATH('Record'), TYPE )) FOR XML PATH('Root')

the result is

<Root>
  <Record>
    <CIMtrek_CIMtrekUniqueID>1917</CIMtrek_CIMtrekUniqueID>
    <CIMtrek_CI_Act>1.000000000000000e+000</CIMtrek_CI_Act>
  </Record>
</Root>

the value is not rounded.

if the value is 10.58 than i have to get 11 . Also the field is varchar if there is no value i have to get empty string than 0 .

what is the mistake i have done here and how to fix the same

Answer 1

It is rounded. What you see is the XML textual representation of SQL Server's float .

If you don't like that, cast it to an integer after rounding.

cast(round([T1].[CIMtrek_CI_Act],0) as int)