使用“包含”查询而不是“完全匹配”查询搜索oracle数据库

Question

I need to search my database which contains user information table. I know to get the result by searching with the query like the following

String query;
StringBuilder sb=new StringBuilder(1024);
sb.append("select * from userinfo where uname=").append(key);
query=sb.toString();

But what I need to do is.

• If the key is abc
• Then I need to search for all data In the database which having the value abc
• For example
• My database contains the data abc , aba , gjabc , abcxyz , hjjabcxyz
• Then I need to retrieve the values abc , gjabc , abcxyz , hjjabcxyz
• Because all above values contains abc in common.

How can I achieve this?

Answer 1

If you are using pure SQL you should use like surrounded with "%". Your query will then return all rows where uname contains "abc". Your query needs to look like this:

select * from userinfo where uname like '%key%'

Answer 2

Correct implementation would use a PreparedStatement.

PreparedStatement ps = conn.prepareStatement("select * from userinfo where uname like ?");
ps.setString(1, key);
ResultSet rs = ps.executeQuery();

of course this misses all error checking and plumbing code :)