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正确使用jQuery select2的initSelection回调与远程数据

[英]Proper usage of jQuery select2's initSelection callback with remote data

I use jQuery select2 plugin in order to retrieve postcodes using the provided ajax callback function as follows: 我使用jQuery select2插件来使用提供的ajax回调函数检索邮政编码,如下所示:

$(document).ready(function() {
    $("#postcodes").select2({
        placeholder : "Search for a postcode",
        multiple : true,
        minimumInputLength : 3,
        ajax : {
            url : "/bignibou/utils/findGeolocationPostcodeByPostcodeStartingWith.json",
            dataType : 'json',
            data : function(term) {
                return {
                    postcode : term
                };
            },
            results : function(data) {
                console.log(data);
                return {
                    results : $.map(data, function(item) {
                        return {
                            id : item.id,
                            text : item.postcode
                        };
                    })
                };
            }
        }
    });
});

Once two postcodes are selected I get the resulting hidden input in the DOM: 一旦选择了两个邮政编码,我就会在DOM中得到hidden input

<input type="hidden" class="bigdrop select2-offscreen" id="postcodes" style="width:600px" name="familyAdvertisement.postcodes" value="4797,4798" tabindex="-1">

The issue I have is that once the form is redisplayed (for instance in the event of some other controls being in error), the selections (ie the two postcodes and especially the text ) don't show in the form although the hidden input does have the two values (ie 4797 and 4798, which are the id s for the postcode). 我遇到的问题是,一旦重新显示表单(例如,在某些其他控件出错的情况下),虽然hidden input确实存在,但选择(即两个邮政编码,尤其是text )不会在表单中显示有两个值(即4797和4798,这是邮政编码的id )。

I am not sure if I have to do another ajax round trip when the form is redisplayed or if there is a better way to go. 我不确定如果重新显示表单或者有更好的方法,我是否必须再做一次ajax往返。

Can anyone please advise? 任何人都可以建议吗?

The initSelection method has to pass the values which has to be present in the select2 initSelection方法必须传递必须存在于select2

Ex: 例如:

$("#postcodes").select2({
    placeholder : "Search for a postcode",
    multiple : true,
    minimumInputLength : 1,
    data:[],
    initSelection : function (element, callback) {
        var data = [{id:1,text:'bug'},{id:2,text:'duplicate'}];
        callback(data);
    }
}).select2('val', ['1', '2']);

Demo: Fiddle 演示: 小提琴

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