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SQL获取与max()关联的列值

[英]SQL get column value associated with max()

I have the following table 我有下表

ID     Version         
---    ----------    
123      1           
124      2           
125      3           
126      4           
127      5           
128      6    

Now I need to get ID value where version# is maximum 现在我需要获取版本号最大的ID值

What I can do is 我能做的是

select ID from tbl where version = (select max(version) from tbl)

I don't want to use this since i need to use this part in a join inside another query and i don't want to complicate things further. 我不想使用它,因为我需要在另一个查询中的联接中使用这一部分,并且我不想进一步使事情复杂化。

You can use select FIRST() : 您可以使用select FIRST()

SELECT FIRST(id) FROM tbl ORDER BY Version DESC

Or limit the number results using LIMIT 1 option: 或使用LIMIT 1选项限制结果数:

SELECT id FROM tbl ORDER BY Version DESC LIMIT 1

You mentioned you need this in a join, so something like this should do it 您提到在联接中需要此功能,因此应执行以下操作

select *
from table_1 as t1
  join (
      select id, 
             row_number() over (order by version desc) as rn
      from table_2
  ) as t2 on t1.id = t2.id and t2.rn = 1

(This is ANSI SQL as you didn't mention a DBMS - but should work on most modern DBMS) (这是ANSI SQL,因为您没有提到DBMS-但应该在大多数现代DBMS上都可以使用)

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