[英]PHP and mySQL “UPDATE” doesn't actually update
So me and my friend came to a conclusion that it's the $_email variable that screws everything up. 因此,我和我的朋友得出了一个结论,那就是$ _email变量使一切搞砸了。 As long as it's hard coded in, it works.
只要它是硬编码的,它就可以工作。 But as soon as it's left as a $_email everywhere, it doesn't.
但是,一旦到处都留下$ _email,它就不会。 The message goes through as "updated" but it doesn't update.
该消息显示为“已更新”,但未更新。
require_once('appVars6.php');
require_once('connectVars6.php');
$_dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$_id = $_GET['id'];
$_queryOne = "SELECT * FROM midterm WHERE id = '$_id'";
$_resultOne = mysqli_query($_dbc, $_queryOne) or die ('Error Querying Database');
while ($_row = mysqli_fetch_array($_resultOne)) {
echo '<form class="update" method="post" action="MT_vjones_udpateRecord.php?id=' . $_id . '">';
echo '<input type="hidden" name="id" id="id" value="' . $_row['id'] . '" />';
echo '<input type="text" name="firstName" id="firstName" value="' . $_row['firstName'] . '" /><br />';
echo '<input type="text" name="lastName" id="lastName" value="' . $_row['lastName'] . '" /><br />';
echo '<input type="text" name="email" id="email" value="' . $_row['email'] . '" /><br />';
echo '</form>';
}
if ( isset($_GET['firstName']) && isset($_GET['lastName']) && isset($_GET['email'])) {
$_id = $_GET['id'];
$_firstName = $_GET['firstName'];
$_lastName = $_GET['lastName'];
$_email = $_GET['email'];
}
else if ( isset($_POST['firstName']) && isset($_POST['lastName']) && isset($_POST['email'])) {
$_id = $_POST['id'];
$_firstName = mysqli_real_escape_string($_dbc, trim($_POST['firstName']));
$_lastName = mysqli_real_escape_string($_dbc, trim($_POST['lastName']));
$_email = mysqli_real_escape_string($_dbc, trim($_POST['email']));
}
else {
echo '<br />';
echo '<p class="error">Sorry, no record was selected.</p>';
}
if(isset($_POST['submit'])) {
if ($_POST['confirm'] == 'Yes') {
//$_dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$_query = "UPDATE midterm " .
"SET email = '$_email'" .
"WHERE id = $_id" ;
$_result = mysqli_query($_dbc, $_query) or die (mysqli_error($_dbc));
mysqli_close($_dbc);
echo '<p>The record of ' . $_firstName . ' ' . $_lastName . ' for ' . $_email . ' was successfully updated.';
}
else {
echo '<p class="error">The record was not updated.</p>';
}
}
else if (isset($_id) && isset($_firstName) && isset($_lastName) && isset($_email)) {
echo '<p>Are you sure you want to update the following record?</p>';
/*echo '<form class="update" method="post" action="MT_vjones_updateRecord.php">';
echo '<input type="text" name="firstName" id="firstName" value="' . $_firstName . '" /><br />';
echo '<input type="text" name="lastName" id="lastName" value="' . $_lastName . '" /><br />';
echo '<input type="text" name="email" id="email" value="' . $_email . '" /><br />';
echo '</form>';*/
echo '<form class="update" method="post" action="MT_vjones_updateRecord.php?id=' . $_id . '">';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="Yes" /> Yes </div><br />';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="No" checked="checked" /> No </div><br /><br />';
echo '<input class="applyBtn" type="submit" value="UPDATE" name="submit" />';
echo '<input type="hidden" name="id" value="' . $_id . '" />';
echo '<input type="hidden" name="firstName" value="' . $_firstName . '" />';
echo '<input type="hidden" name="lastName" value="' . $_lastName . '" />';
echo '<input type="hidden" name="email" value="*testBACK2FUN@test.com*" />';
}
echo '<p><a href="MT_vjones_adminAccess.php"><< Back to the Admin Page</a></p>';
As you can see, we put in the email address in there for testing purposes... 如您所见,我们在此处放置了电子邮件地址以进行测试...
$_query = "UPDATE midterm " .
"SET email = '$_email' WHERE id = '$_id'" ;
should be 应该
$_query = "UPDATE midterm " .
"SET email = $_email".
"WHERE id = $_id " ;
check the id matches what you are intending to update. 检查ID是否与您打算更新的ID相符。 To be sure print the $_id and $_email prior to the update and after.
确保在更新之前和之后打印$ _id和$ _email。
@user710502: You don't need to segregate quotes with double-quotes in PHP. @ user710502:您不需要在PHP中用双引号分隔引号。 It reads it anyway, the only time you might bother is if you are reading from an array eg:
无论如何,它都会读取它,只有您从数组中读取时,您才可能会感到烦恼,例如:
"UPATE midterm SET email='".$POST['email']."'"
Reason is you are using $_
before variable which is not a valid variable declaration. 原因是您在变量前使用
$_
,该变量不是有效的变量声明。
Because $_
is reserved for SUPER GLOBAL
in php (ie $_SESSION,$_SERVER,$_POST,$_GET,$_COOKIE etc)
. 因为
$_
为php中的SUPER GLOBAL
保留(ie $_SESSION,$_SERVER,$_POST,$_GET,$_COOKIE etc)
。
if its not a issue for you then you need to concat your variable as below. 如果这对您来说不是问题,则需要按如下所示连接变量。
$_query = "UPDATE midterm SET email = '".$_email."' WHERE id = '".$_id."'" ;
SOLVED! 解决了! Form issues.
形式问题。
SHOULD BE: 应该:
<?php
require_once('appVars6.php');
require_once('connectVars6.php');
$_dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$_id = $_GET['id'];
$_queryOne = "SELECT * FROM midterm WHERE id = '$_id'";
$_resultOne = mysqli_query($_dbc, $_queryOne) or die ('Error Querying Database');
while ($_row = mysqli_fetch_array($_resultOne)) {
echo '<form class="update" method="post" action="MT_vjones_udpateRecord.php?id=' . $_id . '">';
echo '<input type="hidden" name="id" id="id" value="' . $_row['id'] . '" />';
echo '<input type="hidden" name="firstName" id="firstName" value="' . $_row['firstName'] . '" />';
echo '<input type="hidden" name="lastName" id="lastName" value="' . $_row['lastName'] . '" />';
echo '<input type="hidden" name="email" id="email" value="' . $_row['email'] . '" />';
echo '</form>';
}
if ( isset($_GET['firstName']) && isset($_GET['lastName']) && isset($_GET['email'])) {
$_id = $_GET['id'];
$_firstName = $_GET['firstName'];
$_lastName = $_GET['lastName'];
$_email = $_GET['email'];
}
else if ( isset($_POST['firstName']) && isset($_POST['lastName']) && isset($_POST['email'])) {
$_id = $_POST['id'];
$_firstName = mysqli_real_escape_string($_dbc, trim($_POST['firstName']));
$_lastName = mysqli_real_escape_string($_dbc, trim($_POST['lastName']));
$_email = mysqli_real_escape_string($_dbc, trim($_POST['email']));
}
else {
echo '<br />';
echo '<p class="error">Sorry, no record was selected.</p>';
}
if(isset($_POST['submit'])) {
if ($_POST['confirm'] == 'Yes') {
$_query = "UPDATE midterm " .
"SET email = '$_email'" .
"WHERE id = $_id" ;
$_result = mysqli_query($_dbc, $_query) or die (mysqli_error($_dbc));
mysqli_close($_dbc);
echo '<p>The record of ' . $_firstName . ' ' . $_lastName . ' for ' . $_email . ' was successfully updated.';
}
else {
echo '<p class="error">The record was not updated.</p>';
}
}
else if (isset($_id) && isset($_firstName) && isset($_lastName) && isset($_email)) {
echo '<p>Are you sure you want to update the following record?</p>';
echo '<form class="update" method="post" action="MT_vjones_updateRecord.php?id=' . $_id . '">';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="Yes" /> Yes </div><br />';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="No" checked="checked" /> No </div><br /><br />';
echo '<input type="hidden" name="id" value="' . $_id . '" />';
echo '<input type="text" name="firstName" value="' . $_firstName . '" /><br />';
echo '<input type="text" name="lastName" value="' . $_lastName . '" /><br />';
echo '<input type="text" name="email" value="' . $_email . '" />';
echo '<input class="applyBtn" type="submit" value="UPDATE" name="submit" />';
}
echo '<p><a href="MT_vjones_adminAccess.php"><< Back to the Admin Page</a></p>';
?>
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