使用正则表达式从字符串获取没有扩展名的Filname

Question

I have a string that contains a URL to a file. From that string I like to get just the filename without extension.

For example:

http://path/Lists/Test/Attachments/1/Document Test.docx

From that example I like to get back: Document Test

I already have the following pattern:

(?<=\/)(\w+)(?=\.\w+(\?.*)*$)

But it does not work if the filename contains spaces... How can I change this pattern that it is more flexible?

Answer 1

要仅在扩展名之前捕获字符（不限制文件名可能包含的字符），请使用以下命令：

/[^/]*(?=\.[^.]+($|\?))/

Answer 2

Don't use regex when you don't have to. In this case substring between lastIndexOF / and . would give you what you want.

String data = "Document Testdocx";

int start = data.lastIndexOf('/')+1;
int end = data.lastIndexOf('.');
if (end == -1) end = data.length();

System.out.println(data.substring(start , end));

But if you really must use regex you can try this pattern: (?<=/|^)[^./]+(?=\\\\.\\\\w+$|$)

Answer 3

try

    String s = "http://path/Lists/Test/Attachments/1/Document Test.docx";
    s = s.replaceAll(".+/(.+)\\..+", "$1");
    System.out.println(s);

output

Document Test

Answer 4

([^?]+)\/([^/?]+)(\.[^.\?]+)(\?.*|)$

Even if the URL looks like

http://example.com/foo/bar/baz blah.html?params=true

this can find the file name (without the directory) and the extension.

Probably better would be to parse the URL with java.net.URL , and use URL.getPath().

Answer 5

而不是(?<=/)(\\w+)(?=.\\w+(\\?.)$) ，请尝试(.+?)(\\.[^.]*$|$)