[英]Using Doctrine's MongoDB ODM - How do I find documents by embedded documents' fields?
I have the following Documents: 我有以下文件:
User
document. User
文档。 Site
document Site
文档 Each user has an array of embedded documents inside, each representing an item he follows - a site, a twitter account - with the option to mark specific categories he's interested in. Each embedded document has a reference to the third document - the Site
document (or Twitter
document, etc..). 每个用户都有一系列嵌入式文档,每个用户都代表他所遵循的项目 - 一个站点,一个Twitter帐户 - 可以选择标记他感兴趣的特定类别。每个嵌入式文档都引用第三个文档 -
Site
文档(或Twitter
文件等。)。
The question is - using the MongoDB ODM, how can I get the documents of all the users that chose to follow a given site, using the id of that site ? 问题是 - 使用MongoDB ODM,如何使用该站点的ID获取选择关注给定站点的所有用户的文档?
(see below (after the files) how it is done in the mongodb shell) (见下文(在文件之后)如何在mongodb shell中完成)
User.php user.php的
<?php
use Doctrine\ODM\MongoDB\Mapping\Annotations as ODM;
/**
* @ODM\Document
*/
class User {
/**
* @ODM\Id
* @var string
*/
protected $id;
/**
* @ODM\EmbedMany(
* discriminatorMap={
* "site"="SiteFollow",
* "twitter"="TwitterFollow",
* }
* )
* @var ArrayCollection;
*/
protected $follows;
}
SiteFollow.php SiteFollow.php
<?php
use Doctrine\ODM\MongoDB\Mapping\Annotations as ODM;
/**
* @ODM\EmbeddedDocument
*/
class SiteFollow {
/**
* @ODM\Collection
* @var array
*/
protected $interestingCategories;
/**
* @ODM\ReferenceOne(targetDocument="Site", simple=true)
* @var Site
*/
protected $siteItem;
}
Site.php Site.php
<?php
use Doctrine\ODM\MongoDB\Mapping\Annotations as ODM;
/**
* @ODM\Document
*/
class Site {
/**
* @ODM\Id
* @var string
*/
protected $id;
/**
* @ODM\String
* @var string
*/
protected $name;
/**
* @ODM\String
* @var string
*/
protected $url;
}
An example for a user document in the mongo shell: mongo shell中用户文档的示例:
db.User.findOne()
{
"_id": ObjectId("123"),
"follows": [
{
"interestingCategories": [
"PHP"
]
"siteItem" : ObjectId("OBJECT_ID_OF_SITE_DOCUMENT"),
"_doctrine_class_name" : "site"
}
]
}
Mongo shell command for getting all the users that are following a specific site: Mongo shell命令用于获取跟踪特定站点的所有用户:
db.User.find({"follows.siteItem": ObjectId("OBJECT_ID_OF_SITE_DOCUMENT")})
I found that answer provided by Madarco sometimes doesn't work properly. 我发现Madarco提供的答案有时不能正常工作。 If you are querying for the
$id
field of the reference field in embedded document you may need to pass MongoId
object to the equals()
method. 如果要查询嵌入文档中引用字段的
$id
字段,则可能需要将MongoId
对象传递给equals()
方法。 So in this case it would be: 所以在这种情况下它将是:
$repo = $odm->getRepository('User');
$repo->createQueryBuilder()
->field('follows.siteItem.$id')
->equals(new \MongoId($siteId))
->getQuery()
->execute();
Just query for the $id field of the DbRef field siteItem
in the SiteFollow document (which is in an embedded collection in the User document): 只需在SiteFollow文档中查询DbRef字段
siteItem
的$ id字段(该文档位于用户文档中的嵌入式集合中):
$repo = $odm->getRepository("User");
$repo->createQueryBuilder()
->field("follows.siteItem.$id")
->equals($siteId)
->getQuery()
->execute();
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