[英]Passing parameter to boost::thread no overloaded function takes 2 arguments
From the boost::thread documentation it seems that I can pass parameters to the thread function by doing this: 从boost :: thread文档看来,我可以通过执行以下操作将参数传递给线程函数:
boost::thread* myThread = new boost::thread(callbackFunc, param);
However, when I do this the compiler complains that 但是,当我这样做时,编译器会抱怨
no overloaded function takes 2 arguments
没有重载函数需要2个参数
My code: 我的代码:
#include <boost/thread/thread.hpp>
void Game::playSound(sf::Sound* s) {
boost::thread soundThread(playSoundTask, s);
soundThread.join();
}
void Game::playSoundTask(sf::Sound* s) {
// do things
}
I am using the copy of boost that came with Ogre3d, which I suppose could be very old. 我使用的是Ogre3d随附的boost副本,我认为它可能很旧。 Interestingly, though, I took a look at thread.hpp and it does have the templates for constructors with 2 or more parameters.
不过,有趣的是,我看了一下thread.hpp,它确实具有带有2个或更多参数的构造函数的模板。
The problem is that member functions take an implicit first parameter Type*
, where Type
is the type of the class. 问题在于成员函数采用隐式的第一个参数
Type*
,其中Type
是类的类型。 This is the mechanism by which member functions get called on instances of types, and means you have to pass an extra parameter to the boost::thread
constructor. 这是在类型的实例上调用成员函数的机制,这意味着您必须将一个额外的参数传递给
boost::thread
构造函数。 You also have to pass the address of the member function as &ClassName::functionName
. 您还必须将成员函数的地址传递为
&ClassName::functionName
。
I have made a small compiling and running example that I hope illustrates the use: 我做了一个小的编译和运行示例,希望可以说明该用法:
#include <boost/thread.hpp>
#include <iostream>
struct Foo
{
void foo(int i)
{
std::cout << "foo(" << i << ")\n";
}
void bar()
{
int i = 42;
boost::thread t(&Foo::foo, this, i);
t.join();
}
};
int main()
{
Foo f;
f.bar();
}
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