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可变参数模板参数解包

[英]variadic template arguments unpacking

For each argument I need apply two nested function: 对于每个参数,我需要应用两个嵌套函数:

obj.apply(someFilter(arg)); // arg is one argument, but here
                            // should be an unpacking of args

I don't know how to write unpacking for such case. 我不知道如何为这种情况写解包。

I saw this: 我看到了这个:

 pass{([&]{ std::cout << args << std::endl; }(), 1)...};

on wiki , but again don't know how to apply this for my case. 在维基上 ,但又不知道如何应用于我的情况。

It's actually quite simple: You can put arbitrary expression inside the unpack of an variadic templates argument pack: 它实际上非常简单:您可以将任意表达式放在variadic模板参数包的解包中:

obj.apply(someFilter(arg))...

This will give you the result of obj.apply as a coma seperated list. 这将为您提供obj.apply作为昏迷分隔列表的结果。 You can then pass it to a dummy function: 然后,您可以将其传递给虚拟函数:

template<typename... Args> swallow (Args&&...) {}
swallow(obj.apply(someFilter(arg))...);

To swallow the comma seperated list. 吞下逗号分隔列表。

Of course, this assumes that obj.apply returns some kind of object. 当然,这假设obj.apply返回某种对象。 If not you can use 如果没有,你可以使用

swallow((obj.apply(someFilter(arg)), 0)...);

to make actual (non void ) arguments 制作实际(非void )参数

If you don't know what obj.apply` returns (result might have overloaded the comma operator), you can disable the use of custom comma operators by using 如果你不知道obj.apply`返回什么(结果可能重载了逗号运算符),你可以通过使用禁用自定义逗号运算符的使用

swallow((obj.apply(someFilter(arg)), void(),  0)...);

Should you actually need to evaluate the items in order (which doesn't seem very likely from the question), you can abuse array initialization syntax instead of using a function call: 如果您确实需要按顺序评估项目(这似乎不太可能来自问题),您可以滥用数组初始化语法而不是使用函数调用:

using Alias=char[];
Alias{ (apply(someFilter(args)), void(), '\0')... };

I assume that the code has multiple arg s as a parameter pack? 我假设代码有多个arg作为参数包? Try: 尝试:

obj.apply( someFilter( arg )... );

as parameter unpacking applies to the expression, so each element of the parameter pack get's expanded into someFilter( arg ) . 因为参数解包应用于表达式,所以参数包的每个元素都被扩展为someFilter( arg )

Here is a robust way to do an arbitrary set of actions on a parameter pack. 这是一种在参数包上执行任意操作集的可靠方法。 It follows the principle of least surprise, and does the operations in order: 它遵循最少惊喜的原则,并按顺序执行操作:

template<typename Lambda, typename Lambdas>
void do_in_order( Lambda&& lambda, Lambdas&& lambdas )
{
  std::forward<Lambda>(lambda)();
  do_in_order( std::forward<Lambdas>(lambdas)... );
}

void do_in_order() {}

template<typename Args>
void test( Args&& args ) {
  do_in_order( [&](){obj.apply(someFilter(std::forward<Args>(args)));}... );
}

Basically, you send a pile of lambdas at do_in_order , which evaluates them front to back. 基本上,你在do_in_order发送一堆lambdas,它从前到后评估它们。

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