Bash脚本：使用命令解析字符串而不执行

Question

I have a script that parses an xml in bash. I'm having a problem with one of the elements as it contains a string with some command inside of it: ie:

/usr/bin/printf "%b" "*****  MONITORING  ***** \n\n Notification Type: Critical \n  Host:  &{INTERNETMANAGED_URL00.URL}   \n  Estado: &{INTERNETMANAGED_URL00.Status}    \n Time:    &{INTERNETMANAGED_URL00.Status_Timestamp}    Format: cyymmddhhmmssttt \n Contact to:APPSRV  "|/usr/bin/mail blabla@bla.com -c bllu@bluu.com -r "AAAAA" -s "**  MONITORING - Server URL -Critical  **"

How could I set that string into a variable (and print it) whithout executing the commands inside? I end up getting that printf in my output.

Thanks!

the code looks like this:

while read line
do

    if [[ $line == *"SITNAME"* ]] || [[ $line == *"TEXT"* ]] ; then
        flag=true
    fi


    if [ $flag= 'true' ]; then
        echo "$line"
        writeLine=$writeLine';'"$line"               
    fi


done < file.text

echo $writeLine >> report.out
writeLine=""
flag=false

OUTPUT ON THE ECHO

<![CDATA[/usr/bin/printf "%b" "***** MONITORING  ***** nn Notification Type: Critical n  Host:  &{INTERNETMANAGED_URL00.URL}   n  Stat: &{INTERNETMANAGED_URL00.Status}    n Time:    &{INTERNETMANAGED_URL00.Status_Timestamp}    Format: cyymmddhhmmssttt n Contact to:APPSRV  "|/usr/bin/mail mail@mail.com  -r "MONITORING" -s "**  MONITORING - Server URL -Critical  **"]]>

OUTPUT ON THE FILE

<![CDATA[/usr/bin/printf "%b" "***** MONITORING file1.txt readme.txt file.xml script.sh nn Notification Type: Critical n Host: &{INTERNETMANAGED_URL00.URL} n Stat: &{INTERNETMANAGED_URL00.Status} n Time: &{INTERNETMANAGED_URL00.Status_Timestamp} Format: cyymmddhhmmssttt n Contact to:APPSRV "|/usr/bin/mail mail@mail.com -r "MONITORING" -s "** MONITORING - Server URL -Critical **"]]>

Answer 1

This worked:

writeLine="$writeLine"';'"$line"

...

echo "$writeLine" >> report.out

Thanks all for your time!