[英]MySQL query to order two column, one ASC another DESC
I am trying to prepare a subject wise merit list. 我正在努力准备一个明智的优点列表。 I am using this
mysql query
: 我正在使用这个
mysql query
:
SELECT *
FROM results
ORDER BY qid ASC,
marks DESC
Result is: 结果是:
But what I need is like this (look at marks column, I need to get same qid
rows, ordered by marks
): 但我需要的是这样的(看标记列,我需要得到相同的
qid
行,按marks
排序):
Please anyone help me. 请有人帮帮我。
Update: And this is result.sql
file to create the table in your pc. 更新:这是
result.sql
文件在您的电脑中创建表。
-- phpMyAdmin SQL Dump
-- version 3.5.2.2
-- http://www.phpmyadmin.net
--
-- Host: 127.0.0.1
-- Generation Time: Mar 09, 2013 at 05:40 PM
-- Server version: 5.5.27
-- PHP Version: 5.4.7
SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";
/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
--
-- Database: `ges_omeca`
--
-- --------------------------------------------------------
--
-- Table structure for table `results`
--
CREATE TABLE IF NOT EXISTS `results` (
`exam_id` int(11) NOT NULL AUTO_INCREMENT,
`sid` varchar(50) NOT NULL,
`qid` varchar(100) NOT NULL,
`corrects` int(3) NOT NULL,
`total_qs` int(3) NOT NULL,
`marks` float NOT NULL,
`date_time` datetime NOT NULL COMMENT 'DateTime when user submits the answer script.',
PRIMARY KEY (`exam_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=14 ;
--
-- Dumping data for table `results`
--
INSERT INTO `results` (`exam_id`, `sid`, `qid`, `corrects`, `total_qs`, `marks`, `date_time`) VALUES
(1, 'guest', 'EN_(Set-B)_(07.02.13)', 37, 40, 36.25, '2023-02-13 01:10:00'),
(2, 'guest', 'EN_(Set-B)_(07.02.13)', 11, 40, 10.25, '2013-02-23 01:56:58'),
(3, 'guest', 'P1_(Set-D)_(10.02.13)', 2, 100, 36.25, '2013-02-23 03:42:57'),
(4, 'guest', 'P1_(Set-B)_(09.02.13)', 5, 40, 5, '2013-02-23 03:46:59'),
(5, 'guest', 'EN_(Set-A)_(07.02.13)', 1, 40, 0.25, '2013-02-23 04:46:59'),
(6, 'guest', 'EN_(Set-A)_(07.02.13)', 6, 40, 5.5, '2013-02-23 04:59:59'),
(7, 'guest', 'P1_(Set-D)_(10.02.13)', 10, 100, 9.25, '2013-02-24 08:57:17'),
(8, 'guest', 'P1_(Set-B)_(09.02.13)', 5, 40, 5, '2013-02-24 01:23:50'),
(9, 'guest', 'EN_(Set-D)_(07.02.13)', 0, 40, -0.5, '2013-02-25 12:45:33'),
(10, 'guest', 'EN_(Set-D)_(07.02.13)', 2, 40, 1.5, '2013-02-25 01:45:38'),
(11, 'guest', 'P1_(Set-B)_(09.02.13)', 2, 40, 2, '2013-02-25 04:06:28'),
(12, 'guest', 'EN_(Set-C)_(07.02.13)', 5, 40, 4.5, '2013-02-25 04:42:27'),
(13, 'guest', 'P1_(Set-C)_(10.02.13)', 6, 40, 6, '2013-02-25 05:00:57');
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
This is exactly what you need: 这正是您所需要的:
SELECT *
FROM results
ORDER BY SUBSTRING( qid
FROM 1
FOR 1 ) ASC , marks DESC
I didn't really understand your question but looking on the result, I've noticed that records are sorted by qid
which contains EN
to be the first on the result list. 我没有真正理解你的问题但是看结果,我注意到记录按
qid
排序,其中包含EN
作为结果列表中的第一个。
give this a try, 尝试一下,
SELECT *
FROM tableName
ORDER BY CASE WHEN qid LIKE 'EN%' THEN 0
WHEN qid LIKE 'P1%' THEN 1
ELSE 2
END ASC,
marks DESC
This might help you: 这可能对您有所帮助:
SELECT *
FROM results
ORDER BY SUBSTRING(qid FROM 1 FOR 9) ASC,
marks DESC
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.