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在MYSQL PHP中获取与GROUP_CONCAT相关的数据

[英]To get data related to the GROUP_CONCAT in MYSQL PHP

Table 1 表格1

表格1

Table 2 表2

表2

This is the result for Those Two table i got By using this query: 这是通过使用此查询得到的那两个表的结果:

SELECT t1.*, GROUP_CONCAT(t2.content_id) 
FROM news_categories t1 
LEFT JOIN news_content t2 
    ON t2.cat_ids = t1.cat_id 
GROUP BY t1.cat_id

Result generated 结果产生

结果

How can I get the information in table2 from the result(table) GROUP_CONCAT(t2.content_id) related to the content_id ? 如何从与content_id相关的result(table) GROUP_CONCAT(t2.content_id)获取table2中的信息?

and Retrive those data from table2 Using PHP 并使用PHP从table2中检索这些数据

Well, you got a one-to-many relationship here. 好吧,您在这里有一对多的关系。 Meaning one row in table1 can be related to 0-n rows in table2. 意味着表1中的一行可以与表2中的0-n行相关。

If you you group by the primary key of table1 you limit the result to one result row for each row in table one, by using GROUP_CONCAT(table2_col) you concatenate all matching rows of the table2_column with a separator which is comma by default. 如果按表1的主键进行分组,则将结果限制为表1中每一行的一个结果行,通过使用GROUP_CONCAT(table2_col)您可以将table2_column的所有匹配行连接在一起,默认情况下使用逗号分隔。

Play with the following queries: 玩以下查询:

SELECT
     t1.*, 
     GROUP_CONCAT(t2.content_id) AS content_ids,
     GROUP_CONCAT(t2.title) AS content_titles
FROM 
    news_categories t1 
        LEFT JOIN news_content t2 ON t2.cat_ids = t1.cat_id 
GROUP BY t1.cat_id

Or 要么

SELECT
     t1.*, 
     t2.*
FROM 
    news_categories t1 
        LEFT JOIN news_content t2 ON t2.cat_ids = t1.cat_id 

I recommend to write out the columns you want, instead of using .* 我建议写出所需的列,而不要使用。*

EDIT 编辑

To separate the concatenated values in php have a look at explode 要分离php中的串联值,请看看explode

You fetch the data as usual eg 您照常获取数据,例如

$result = mysqli_query( $query );
while ( $row = mysqli_fetch_assoc( $result ) ) {
    print_r( $row );
}

Have a look at this examples 看看这个例子

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